Ask question

Ask question

All categories

3 years ago

11

How much force would be required to accelerate a 2kg object at a rate of 15m/ sec?

1 answer:

Anna007 [38]3 years ago

5 0

Im saying a or b but i pick B

You might be interested in

You toss a ball straight upward, in a positive direction. The ball falls freely under the influence of gravity. At the highest p

Sindrei [870]

Answer:

B.) its velocity is zero and its acceleration is negative (downward).

Explanation:

When the ball is thrown upwards in the air, the ball starts with its velocity being high and positive upwards against the force of gravity. Due to force of gravity pulling the object to the center of the earth, its velocity decreases as it reaches the maximum height where the velocity is instantaneously zero. At this maximum height its acceleration is -9.81 m/s².

4 0

3 years ago

An electron moves with a speed of 5.0 x 10^4m/s

Firlakuza [10]

Answer:

$F=1.6\times 10^{-15}\ N$

Explanation:

Given that,

Speed of the electron, $v=5\times 10^4\ m/s$

Magnetic field, B = 0.20 T

We need to find the magnitude of magnetic force on the electron. The formula for the magnetic force is given by :

$F=qvB\ sin\theta$

Here, $\theta=90^{\circ}$

$F=qvB$ , q is the charge on electron

$F=1.6\times 10^{-19}\times 5\times 10^4\times 0.2$

$F=1.6\times 10^{-15}\ N$

So, the magnitude of the magnetic force on the electron is $1.6\times 10^{-15}\ N$ . Hence, this is the required solution.

4 0

4 years ago

Scientists use models to

xxTIMURxx [149]

D Is Thw Correct answer

3 0

4 years ago

A particle with kinetic energy equal to 282 J has a momentum of magnitude 26.4 kg · m/s. Calculate the speed (in m/s) and the ma

masha68 [24]

Answer:

$v=21.36\,\,\frac{m}{s}\\$

$m=1.2357\,\,kg$

Explanation:

Recall the formula for linear momentum (p):

$p = m\,v$ which in our case equals 26.4 kg m/s

and notice that the kinetic energy can be written in terms of the linear momentum (p) as shown below:

$K=\frac{1}{2} m\,v^2=\frac{1}{2} \frac{m^2\,v^2}{m} =\frac{1}{2}\frac{(m\,v)^2}{m} =\frac{p^2}{2\,m}$

Then, we can solve for the mass (m) given the information we have on the kinetic energy and momentum of the particle:

$K=\frac{p^2}{2\,m}\\282=\frac{26.4^2}{2\,m}\\m=\frac{26.4^2}{2\,(282)}\,kg\\m=1.2357\,\,kg$

Now by knowing the particle's mass, we use the momentum formula to find its speed:

$p=m\,v\\26.4=1.2357\,v\\v=\frac{26.4}{1.2357} \,\frac{m}{s} \\v=21.36\,\,\frac{m}{s}$

4 0

3 years ago

A square sheet of rubber has sided that are 20 cm long. If you stretch one side so that it is twice as long. What is the new are

Anika [276]

Answer:ignore this it was wrong

Explanation:

3 0

4 years ago