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Andru [333]
3 years ago
13

What is the measure of BDA?

Mathematics
1 answer:
Kisachek [45]3 years ago
7 0

Answer:

it's A.

sorry if you get it wrong but I belive it is A

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Determine the next step for solving the quadratic equation by completing the square.
nexus9112 [7]

\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

the idea behind the completion of the square is simply using a perfect square trinomial,  hmmm usually we do that by using our very good friend Mr Zero, 0.

if we look at the 2nd step, we have a group as x² - x, hmmm so we need a third element, which will be squared.

keeping in mind that the middle term of the perfect square trinomial is simply the product of the roots of "a" and "b",  so in this case the middle term is "-x", and the 1st term is x², so we can say that

\stackrel{middle~term}{2(\sqrt{x^2})(\sqrt{b^2})~}~ = ~~\stackrel{middle~term}{-x}\implies 2xb~~ = ~~~~ = ~~-x \\\\\\ b=\cfrac{-x}{2x} \implies b=-\cfrac{1}{2}

so that means that our missing third term for a perfect square trinomial is simply 1/2, now we'll go to our good friend Mr Zero, if we add (1/2)², we have to also subtract (1/2)², because all we're really doing is borrowing from Zero, so we'll be including then +(1/2)² and -(1/2)², keeping in mind that 1/4 - 1/4 = 0, so let's do that.

-3~~ = ~~-2\left[ x^2-x+\left( \cfrac{1}{2} \right)^2 ~~ - ~~\left( \cfrac{1}{2} \right)^2\right]\implies -3=-2\left(x^2-x+\cfrac{1}{4}-\cfrac{1}{4} \right) \\\\\\ -3=-2\left(x^2-x+\cfrac{1}{4} \right)+(-2)-\cfrac{1}{4}\implies -3=-2\left(x^2-x+\cfrac{1}{4} \right)+\cfrac{1}{2} \\\\\\ -3-\cfrac{1}{2}=-2\left(x^2-x+\cfrac{1}{4} \right)\implies -\cfrac{7}{2}=-2\left(x-\cfrac{1}{2} \right)^2\implies \cfrac{7}{4}=\left(x-\cfrac{1}{2} \right)^2

~\dotfill\\\\ \pm\sqrt{\cfrac{7}{4}}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}+\cfrac{1}{2}=x \implies \cfrac{\pm\sqrt{7}+1}{2}=x

8 0
2 years ago
How do I solve this
poizon [28]

Answer:

8x^{-2} a^{7}

Step-by-step explanation:

combine by putting together

3 0
4 years ago
Examine this system of linear equations. y – 3x = –2, y = 4. Which is a solution of the system of equations?
Svetlanka [38]

Answer:the third option is the correct answer

Step-by-step explanation:

The given system of linear equations is expressed as

y – 3x = –2 - - - - - - - - - - - -1

y = 4 - - - - - - - - - - - - - 2

The first step is to substitute equation 1 into equation 2. It becomes

4 – 3x = –2

Subtracting 4 from the left hand side and the right hand side of the equation, it becomes

4 - 4 - 3x = –2 - 4

- 3x = - 6

Dividing the left hand side and the right hand side of the equation by - 3, it becomes

- 3x/ - 3 = - 6/ - 3

x = 2

(2, 4)

4 0
4 years ago
Read 2 more answers
Find the slope and y-intercept of the graph of the equation. y=2x+4
jeyben [28]

Answers:

Slope: 2

y-intercept: 4

6 0
3 years ago
2(x +10)-17 = 5 + 2x - 2<br> 22
muminat
The correct answer is no solution
4 0
3 years ago
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