Answer:
First we need to name some of the variables we are given:n = 38 the sample sizex = 6.88 the sample mean = 1.86 the population standard deviationWe need to find a 90% confidence interval for the mean price per 100 lbs of watermelon: = 1-.90 = .10/2 = .05z(/2) = -1.64-z(/2) = 1.64This can give us a probability expression:P(-1.645 < z < 1.645) = .90The margin of error is calculated with the formula: E = z(/2)(/√n)E = 1.645(1.86/√38) = $.4963(300) = $148.89 Then to calculate the upper and lower limit we add and subtract E from x:lower limit = 6.88 - .4963 = $7.38(300) = $2214upper limit = 6.88 + .4963 = $6.38(300) = $1914Note: We multiply the E, upper and lower limits by 300 because 15 tons is 30000lbs and we need the price per 100 lbs, so we divide 30000/100 and get 300.
Step-by-step explanation:
Answer:
1/5
Step-by-step explanation:
We assume the events are independent, so the probability of the joint event is the product of the probabilities of the individual events.
P(Y or W) = 2 letters of 5 = 2/5
P(easy) = 1 of 2 kinds = 1/2
The product of these is ...
P((Y or W) and (easy)) = (2/5)(1/2) = 1/5
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In both cases, we have to assume that each of the possible outcomes is equally likely.
With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
How many grandchildren do they have?
3 ways (uncertain)
1 red or blue or green + 3 other colours
