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Pepsi [2]
3 years ago
10

I need help with this PLEASE

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

1230 I believe I think area is when u add em all up that's what I did good luck

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Let f(x)=(8x^4-3)^3 and g(x)=8x^4-3 given that f(x)=(h g)(x) , find h(x)
Harman [31]

<u>Answer:</u>

h(x) = x^{3}

<u>Step-by-step explanation:</u>

f(x) = (8 \times x^{4}- 3)^{3} ------------(1) (given)

g(x) =(8 \times x^{4}- 3) -------------(2) (given)

so,

f(x) = h(g(x)) (given)

    = (g(x))^{3}-----(from (1) and (2))

⇒h(k) = k^{3}-----(taking g(x) = k)

⇒h(x) = x^{3} is the function.

8 0
3 years ago
What is the range of the relation below?
Ilya [14]

Answer:

b

Step-by-step explanation:

I had the same question

7 0
3 years ago
Please help!! Evaluate the piece wise function at x=-4 and x=4.
hodyreva [135]

x = -4, so use the first equation, x^2 = -4^2 = -16

x = 4, use 3rd equation, sqrt(x) = sqrt(4) = 2

4 0
3 years ago
What is the area of a rectangular holding pond with length 8/15 mile and width 1/6 mile?
SSSSS [86.1K]

as you already know, the area of a rectangle is just length*width, so is just the product of those two.


\bf \cfrac{8}{15}\times \cfrac{1}{6}\implies \cfrac{8}{6}\times \cfrac{1}{15}\implies \cfrac{4}{3}\times \cfrac{1}{15}\implies \cfrac{4}{45}

4 0
3 years ago
Read 2 more answers
Given f'(x) = (1 − x)(4 − x), determine the intervals on which f(x) is increasing or decreasing.
Sophie [7]
The critical points are at x = 1 and x = 4 giving you the intervals (-inf, 1), (1, 4) and (4, inf).

By substituting x values in these 3 intervals, you can see that f'(x) is positive in the first and third intervals and negative in the second interval.

This means that f(x) is increasing in the first and third intervals and decreasing in the second interval.

The answer is D.
8 0
3 years ago
Read 2 more answers
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