You are given a set of data with a mean of 50 and standard deviation of 8. Using the normal curve, give an example of an outlier
1 answer:
Answer:
<u>Anything less than 26, and greater than 74.</u>
Step-by-step explanation:
In normal distribution, the outlier is more than e ≈ 2.72 standard deviations above quartile 3, and e standard deviations below quartile 1. These quartiles are divisions that make up what is known as the innerquartile range(IQR). Which defines the variability of a data set given by IQR = Q3-Q1.
Given that the mean of this data is 50, and the standard deviation is 8.
Our outliers are anything less than 26, and anything greater than 74. Since outliers are anything outside the mean plus and minus the standard deviation times 3
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Answer:
Maximum area = 800 square feet.
Step-by-step explanation:
In the figure attached,
Rectangle is showing width = x ft and the side towards garage is not to be fenced.
Length of the fence has been given as 80 ft.
Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced
80 = x + x + y
80 = 2x + y
y = (80 - 2x)
Now area of the rectangle A = xy
Or function that represents the area of the rectangle is,
A(x) = x(80 - 2x)
A(x) = 80x - 2x²
To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.
= 80 - 4x
A'(x) = 80 - 4x = 0
4x = 80
x =
x = 20
Therefore, for x = 20 ft area of the rectangular patio will be maximum.
A(20) = 80×(20) - 2×(20)²
= 1600 - 800
= 800 square feet
Maximum area of the patio is 800 square feet.
