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3 years ago

Pls help i dont get it

Mathematics

2 answers:

MArishka [77]3 years ago

7 0

Answer:

The slope of the table is 1/5

Step-by-step explanation:

$m=\frac{3-1}{10-0}$

$m=\frac{2}{10}$

$m=\frac{1}{5}$

baherus [9]3 years ago

5 0

Answer:

What is it?

Step-by-step explanation:

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4) The line -3x + 4y = 8 is transformed by a dilation centered at the origin. Which linear equation could represent its image?

Dimas [21]

Answer:

4) The linear equation which could represent its image is y = $\frac{3}{4}$ x + 8 ⇒ (2)

5) The equation of the image of the line is y = $\frac{3}{2}$ x - 3 ⇒ (4)

Step-by-step explanation:

Dilation does not change the slope of a line but changes the y-intercept

Dilation of a line segment is longer or shorter by ratio that equal to the scale factor of dilation

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b its y-intercept

Let us put the given equation in the slope-intercept form to find its slope

∵ The line -3x + 4y = 8 is transformed by a dilation centered at

the origin

- Add 3x to both sides

∴ 4y = 3x + 8

- Divide both sides by 4

∴ y = $\frac{3}{4}$ x + 2 ⇒ the equation of the line before dilation

- By comparing it with the form above, then m = $\frac{3}{4}$ , so the

equation after dilation has the same slope

∵ The slope of the line before dilation is $\frac{3}{4}$

∴ The slope of the line after dilation is $\frac{3}{4}$

∵ The equation that has the slope $\frac{3}{4}$ is y =

∴ The equation of the image of the line is y = $\frac{3}{4}$ x + 8

The linear equation which could represent its image is y = $\frac{3}{4}$ x + 8

∵ The equation of the line is y = $\frac{3}{2}$ x - 4

∵ The scale factor of dilation is $\frac{3}{4}$

- Dilation dose not change the slope of the line

∴ The slope of the image after dilation is $\frac{3}{2}$

- Dilation changes the y-intercept, to find it multiply the scale

factor of dilation by the y-intercept of the line before dilation

∵ The y-intercept of the line is (0 , -4)

- Multiply it by $\frac{3}{4}$

∵ $\frac{3}{4}$ × -4 = -3

∴ The y-intercept of the image is (0 , -3)

∴ The equation of the image of the line is y = $\frac{3}{2}$ x - 3

3 0

3 years ago

A sphere has a diameter of 14 units. what is the volume of the sphere in cubic units ? If a cylinder have the same radius as th

Dimas [21]

Answer:

Therefore, the volume of sphere is 1436.03 cubic units.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

line y = 2x+1 is transformed by a dialation with a scale factor of two and centered at (0,-4). what is the equation of the image

Gekata [30.6K]

Answer: y = 2x + 6

Step-by-step explanation:

Here the equation of line,

y = 2x + 1

y-intercept of the line is, (0, 1)

And, the slope of the line is 2.

Since, If a point (x,y) is dilated by a scale factor k about a point (a,b),

Then transformed point are get by,

$(x,y)\rightarrow (k(x-a)+a, k(y-b)+b)$

Thus, The transformed point of point (0,1) when dilation is occur by the scale factor 2 about the point (0,-4),

$(0,-4)\rightarrow (2(0-0)+0, 2(1+4)-4)$

$(0,-4)\rightarrow (0, 6)$

Thus, the point of the new line is (0,6)

And, the slope of the new line is 2 ( because in the dilation, the slope of the line does not change)

Thus, the equation of new line,

(y - 6) = 2 (x - 0)

y - 6 = 2x

y = 2x + 6

5 0

3 years ago

N = 27 divided (4 + 5)

frozen [14]

The answer to this question is n = 3

6 0

3 years ago

PLEASE HELP QUICKLY 25 POINTS

Natalija [7]

Answer:

○ $\displaystyle \pi$

Step-by-step explanation:

$\displaystyle \boxed{y = 3sin\:(2x + \frac{\pi}{2})} \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{4}} \hookrightarrow \frac{-\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3$

OR

$\displaystyle \boxed{y = 3cos\:2x} \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3$

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of $\displaystyle y = 3sin\:2x,$ in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted $\displaystyle \frac{\pi}{4}\:unit$ to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD $\displaystyle \frac{\pi}{4}\:unit,$ which means the C-term will be negative, and by perfourming your calculations, you will arrive at $\displaystyle \boxed{-\frac{\pi}{4}} = \frac{-\frac{\pi}{2}}{2}.$ So, the sine graph of the cosine graph, accourding to the horisontal shift, is $\displaystyle y = 3sin\:(2x + \frac{\pi}{2}).$ Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit $\displaystyle [-1\frac{3}{4}\pi, 0],$ from there to $\displaystyle [-\frac{3}{4}\pi, 0],$ they are obviously $\displaystyle \pi\:units$ apart, telling you that the period of the graph is $\displaystyle \pi.$ Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at $\displaystyle y = 0,$ in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

7 0

2 years ago

Read 2 more answers

Pls help i dont get it ​

Pls help i dont get it