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Vedmedyk [2.9K]
2 years ago
10

Calculate the volume of a cuboid with length 5.6m breadth 4.1m, height 3.4m

Mathematics
1 answer:
lidiya [134]2 years ago
6 0

Answer:  78.064 cubic meter

Step-by-step explanation:

volume of a cuboid=length × breadth × height.

                                =5.6*4.1*3.4

                                =78.064 cubic meter

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The answer to c plz
NikAS [45]

Answer:

≈ 30.63 cm²

Step-by-step explanation:

The shaded area is calculated by subtracting the area of the inner circle from the area of the outer circle.

outer circle has radius = 8 ÷ 2 = 4 and inner circle has radius = 5 ÷ 2 = 2.5

shaded area = πr₁² - πr₂² (r₁ is outer and r₂ is inner )

A = π (4² - 2.5²)

   = π(16 - 6.25) = 9.75π ≈ 30.63 cm²

           

5 0
3 years ago
Find the area of the shaded region​
Setler79 [48]

Answer:

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Step-by-step explanation:

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2 years ago
Solve for s.<br> 0.5s +1= 7+ 4.58<br> S =?
Lana71 [14]

Answer:

s = 21.16

Step-by-step explanation:

0.5s +1= 7+ 4.58

Combine like terms

0.5s +1=11.58

Subtract 1 from each side

0.5s +1-1= 11.58-1

.5s = 10.58

Multiply by 2

.5s *2 = 10.58*2

s = 21.16

4 0
2 years ago
Read 2 more answers
Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le
Helen [10]

Answer: \overline{AC}= 12.5

Step-by-step explanation: The triangle ABC and its altitude \overline{BD} is represented in the figure below.

<u>Altitude</u> is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of \overline{BD}, now we have two similar triangles, which means that ratios of corresponding sides are equal:

\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}

\overline{BD}^{2}=\overline{BC}.\overline{AD} (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}

\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2} (2)

Substituting (2) into (1):

\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}

We want to find f, so:

\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}

f=\frac{10^{2}-5^{2}}{10}

f = 7.5

The length of \overline{AC} is

\overline{AC}=f+5

\overline{AC}=7.5+5

\overline{AC}=12.5

The length of the hypotenuse of triangle ABC is 12.5 units.

5 0
2 years ago
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If AC is parallel to DF, what is the measure, in degrees, of ∠ABD
Kamila [148]

Answer:

Yes it is parellell

Step-by-step explanation:

3 0
3 years ago
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