Answer:
Constant because it's just the number itself while 2 is a coefficient for it's accompanied by i.
Answer:
The answers are 0, -6, 6
Step-by-step explanation:
So we have the equation:
6x(x^2 - 36) = 0
Multiply 36 x 6(the outside number)
6x(x^2 - 216)
Add x and x^2
6x^3 - 216 = 0
Now lets get rid of the exponents.
Split -216 into two equations. 6 x -6 = -216.
So the equations we have are:
(x + 6) and (x - 6)
Put this together with the 6x we have:
6x(x + 6)(x - 6) = 0
Now separate them into three problems:
6x = 0, x + 6 = 0, x - 6 = 0
Find x for all of them.
The answers are 0,-6, and 6.
Btw this is what I think you meant by solving it. If I got the wrong idea, let me know and I’ll fix it.
The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)
Lets write this out:-
20 ÷ 2 × (5+5).
To answer this we will use the Oder Of operations.
PEMDAS.
Since there is parenthesis, we will 1st solve that.
20 ÷ 2 × (5 + 5)
20 ÷ 2 × (10)
Next we will do division.
10 × (10).
Finally multiply.
100.
So, 20 ÷ 2 × (5 + 5) = 100.
Hope I helped ya!!
Answer:
8(x+3)
Step-by-step explanation:
When you distribute the 8 to the x, it will become 8x.
when you distribute the 3 to the 8 (multiplying them) you will get 24.
Then that will make the original equation.