Well. If you get 29% of 5 cars that is 145%. This was a little confusing but I am defiantly sure it is correct. I like to use simpler numbers to see if I am doing the work right. So I said if he has a 50 % likely hood to find a car that was expired and had 1 car. It would be 50 percent. Now if he had 2nt got it the first time it would be a 100 % chance to find the car expired . Hope I didn’t co fuse you more
Answer:
2 c (c^4 + 22 c^3 + 121)
Step-by-step explanation:
Factor the following:
2 c^5 + 44 c^4 + 242 c
Factor 2 c out of 2 c^5 + 44 c^4 + 242 c:
Answer: 2 c (c^4 + 22 c^3 + 121)
Based on the absolute deviations and the predicted values, the sum of absolute deviations will be <u>4.8.</u>
<h3>What would be the sum of absolute deviations from predicted values?</h3>
This can be found as:
= ∑ (Observed value - Predicted value)
The observed values are given in the table and the predicted values will be calculated using y = 3.6x - 0.4.
Solving gives:
= [3 - (3.6 x 1 - 0.4)] + [7 - (3.6 x 2 - 0.4)] + [ 9 - (3.6 x 3 - 0.4)] + [14 - (3.6 x 4 - 0.4)] + [15 - (3.6 x 5 - 0.4)] + [21 - (3.6 x 6 - 0.4)] + [25 - (3.6 x 7 - 0.4)]
= 0.2 + 0.2 + 1.4 + 0 + 2.6 + 0.2 + 0.2
= 4.8
Find out more on absolute deviation at brainly.com/question/447169.
The answer is mean absolute deviation
