And its 6 600 and 202 and add 100 which means it will be 12 THATS your answer
Answer:
5x + 16
Step-by-step explanation:
the first thing you do in this equation is to distribute the 2 into x + 6
you get
2x + 12 + 3x + 4 = ?
then you must put the 2x and the 3x together
5x + 12 + 4
and you can then add the 12 and 4
5x + 16
The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
= 
(-)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -x + 3
y = -.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
The Area of the platform is 33m²
Step-by-step explanation:
As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m
Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m
Since the platform is five-sided, the figure can be broken down into constituting parts
- Parallelogram ║ABCE
- Δ DCE
Are of the figure= Area of ║ABCE+ area Δ DCE
Area of ║ABCE= breadth * height
= 6*4 ⇒24m
²
Area Δ DCE= ½*(base)(height)
Putting the value of base is 6m and height as 3m
Area Δ DCE= ½*6*3
=9m
²
Total area= 24+9= 33m
²
Detecting...<span>
</span>Your answer would be:
