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cricket20 [7]
3 years ago
12

Helllllppp please asap

Mathematics
1 answer:
BartSMP [9]3 years ago
5 0

Answer:

1). a = 9.42 m

2). b = 6.37 m

3). c = 4.48 m

Step-by-step explanation:

In the figure attached,

By applying tangent rule in triangle ADE,

tan47 = \frac{h}{c}

c = \frac{h}{\text{tan}47}

c = \frac{4.8}{\text{tan}47}

c = 4.476

c ≈ 4.48 m

Now we apply the same rule in triangle ACE,

tan37° = \frac{h}{b}

b = \frac{h}{\text{tan}37}

b = \frac{4.8}{1.0724}

b = 6.37 m

Now apply the tangent in triangle ABE,

tan27° = \frac{h}{a}

a = \frac{h}{\text{tan}27}

a = \frac{4.8}{0.5095}

a = 9.42 m

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Answer:

99% CI:

-4.637\leq\mu_v-\mu_o\leq 3.737

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

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The MSE can be calculated as

MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65

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The standard deviation then becomes

s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

\Delta M=M_v-M_o=5.10-5.55=-0.45

Then the confidence interval can be constructed as

\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737

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3 years ago
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