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3 years ago

Ill give braniliest

Mathematics

2 answers:

nika2105 [10]3 years ago

8 0

Answer: I would answer but the person who answered has the correct answer

Step-by-step explanation:

Imma go help someone who needs help with math ;)

erastova [34]3 years ago

4 0

Answer:

The fourth term is 20

Step-by-step explanation:

first term =50

term rule = n-10

if first term is 50

second term =50-10=40

third term =40-10=30

fourth term =30-10=20

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Please help, I need this answer

Rom4ik [11]

Answer:

6.4

Step-by-step explanation:

By the Pythagorean Theorem:

$c=\sqrt{5^2+4^2}= \\\\\sqrt{25+16}= \\\\\sqrt{41}\approx 6.4$

Hope this helps!

6 0

3 years ago

Read 2 more answers

f(x)=-3x+12 represents the amount of ounces of juice left in a bottle after you take x gulps. How many gulps did you take if the

notka56 [123]

Answer:

3 gulps

Step-by-step explanation:

In this problem, f(x) = 3. Plug this into the equation:

3 = -3x + 12

Solve for x:

3 - 12 = -3x + 12 - 12

-9 = -3x

-9 / -3 = -3x / -3

3 = x

3 gulps

7 0

3 years ago

Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

HELP ROUND 479065.389037 TO THE NEAREST THOUSAND

exis [7]

ROUND 479065.389037 TO THE NEAREST THOUSAND = <span>479,000</span>

8 0

3 years ago

Read 2 more answers

Set up and solve an equation to find the value of x

gregori [183]

X° + 123° + 90° = 360° (angles at a point)
x° = 360° - 90° -123°
x° = 147°

The answer of x is 147°

Hope I can help you :)

3 0

3 years ago