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3 years ago

Select the correct answer from each drop-down menu.

Mathematics

1 answer:

evablogger [386]3 years ago

6 0

Answer:

Graph A ,appears to decrease less

Step-by-step explanation:

In the word problem it asked us which graph seem to have "Slight Decrease"means if obeserve the graph it shows graph A.

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Which sets of points are collinear?

schepotkina [342]

A set of points is collinear if the points lie on the same straight line.

From the given figure,
A) Z, J, and C are not collinear
B) H, B, and C are collinear
C) H, B, and K are not collinear
D) Z, K, and R are collinear

Answer: B and D

5 0

3 years ago

Read 2 more answers

The lines below are parallel if the slope of the green line is -2 what is the slope of the red line

kati45 [8]

Answer:

-2

Step-by-step explanation:

Since they are parallel, they have the same slope. This will be true for any set of lines.

8 0

3 years ago

What is the mean?<br> 9.12.34.6.8.9.

NISA [10]

Answer:

Step-by-step explanation:

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

4 0

2 years ago

Read 2 more answers

Anyone help me, please I need help<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%205%7D%20%20%3D%20%208%20%5Csqrt%5B%5

Ilya [14]

Answer:

No Real Solutions.

Step-by-step explanation:

√(x-5)=8√(x-2)

Square on both sides,

(√(x-5))^2=(8√(x-2))^2

or,(x-5)=64(x-2)

or,x-5=64x-128

or,-5+128=64x-x

or,123/63=x

Therefore, x=41/21

If you plug x=41/21 in √(x-5)=8√(x-2) you do not get equals, so the problem has no real solutions.

7 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$