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REY [17]
3 years ago
10

Find the value of n so that the line perpendicular to y = (-1/4)x-1 passes through the points (n, 3) and (4,11).

Mathematics
1 answer:
Tresset [83]3 years ago
8 0

Answer:

2

Step-by-step explanation:

You'll need to find the reciprocal of m. -1/4 is your is your m and when you find the reciprocal you flip the number to 4/1 or 4 and change the negative to a positive. Then graph (4,11), you don't need to worry about your y intercept, b, or -1. On your graph go down 4 and over one to the left because it's positive the line should be going like " / "  <-- that. Keep going down until your y is three and whatever your x is, is your answer. Ex: (4,11) (3,7) (<u>2</u>,3). Hopefully, you understand :)

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5. Each pair of polygons below are similar. Show your work! Solve for x:
BartSMP [9]

Answer:

x = 10

Step-by-step explanation:

30/35 = (6x-6)/63

210x - 210 = 1890

210x = 2100

x = 10

4 0
3 years ago
The sum of two numbers is 20. Their difference is 14. Find the numbers.
Mila [183]
3 and 17
17-3=14

hope that helps
5 0
3 years ago
Read 2 more answers
Factor completely 4x^2 +25+6
malfutka [58]

Answer:

Look at the explanation

Step-by-step explanation:

4x^2+25x+6

(4x+1)(x+6)

Hope this helps!

7 0
3 years ago
Read 2 more answers
When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
aleksandr82 [10.1K]

Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

x^2-(3x+528)

The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

But we know that x is positive, so we only accept the solution x = 27

6 0
3 years ago
PLEASE HELP WITH THIS I HAVE NO IDEA HOW TO SOLVE!!!!
VARVARA [1.3K]
Write the vertex form of the equation and find the necessary coefficient to make it work.
.. y = a*(x +3)^2 -2
.. = ax^2 +6ax +9a -2

You require the y-intercept to be 7. So, for x=0, you have
.. 9a -2 = 7
.. 9a = 9
.. a = 1

The equation you seek is
.. y = x^2 +6x +7

4 0
3 years ago
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