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Step2247 [10]
3 years ago
12

PLEASE HELP!!!!!

Mathematics
2 answers:
Archy [21]3 years ago
8 0
The first thing to do in this case is to perform the division and then compare with the simplified expression to determine the values of a, b, c and d.
 We have then:
 (12xy ^ 3 + 4x ^ 2y ^ 5) / (4xy ^ 2) =
 3x (1-1) and ^ (3-2) + x ^ (2-1) and ^ (5-2) =
 3x (0) and ^ (1) + x ^ (1) and ^ (3)
 Then, comparing with the simplified expression:
 3x ^ ay ^ b + 1x ^ cy ^ d
 The value of a is
 a = 0
 answer
 the value of a is 0
Yuki888 [10]3 years ago
7 0
<span>If we want to calculate 12xy^3/4xy^2, we divide the constants (12/4) and arrive 3, but then we simply subtract the power of the variable in the denominator from the power of the variable in the numerator. Here for x, that is 1 - 1, leaving us with 0. Thus the value of a is 0, and the x^0 term would just become a 1, allowing us to essentially remove it since it simply is multiplying by 1.</span>
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