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Rufina [12.5K]
3 years ago
5

What is the area of a 6x6x6 equilateral triangle?

Mathematics
2 answers:
NARA [144]3 years ago
6 0
A 6x6x6 triangle
we cut it into half so consider one half
its 6x3
by Pythagoras theorem, we can find the length of the triangle sqrt (6^2 -3^2) = a
then we can find the area of the triangle by
1/2 x base x height
=
1/2 x 6 x a
maw [93]3 years ago
4 0
216 cubic units bc 6x6=36 and then 36x6=216
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In order to get an A in science, Jack must get at least a 92% on his next test. If test has 30 questions,what is the minimum num
Neko [114]
Jack must score 28 problems correct. To get a 92% he must answer 92% of the 30 questions right. which means 0.92*30=27.6, but it is not possible to score 0.6 of a problem right so you would round to 28, which guarantees Jack scores a 92 because if we round down, Jack would score less than a 92
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3 years ago
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Eric noticed that his basil plant grows 5 cm every day. He starts recording the height when the plant is 22 cm tall. He wants to
slava [35]
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5 0
3 years ago
A teacher is giving her students a lesson on inequalities and asks the class to suggest points that are included in the solution
Slav-nsk [51]
Neither of the students are correct
8 0
3 years ago
Consider these functions
vitfil [10]

9514 1404 393

Answer:

  C.  3x² +24

Step-by-step explanation:

Use the given function definitions and simplify.

  g(f(x))=g\left(\dfrac{1}{3}x^2+4\right)\\\\=9\left(\dfrac{1}{3}x^2+4\right)-12\\\\=3x^2+36-12\\\\\boxed{g(f(x))=3x^2+24}\qquad\textbf{matches C}

5 0
3 years ago
He takes a random sample of 49 recent charterholders and computes a mean salary of $172,000 with a standard deviation of $35,000
uysha [10]

Answer:

the 90% of confidence intervals for the average salary of a CFA charter holder

 (1,63,775 , 1,80,000)

Step-by-step explanation:

<u>Explanation</u>:-

random sample of n = 49 recent charter holders

mean of sample (x⁻) =  $172,000

standard deviation of sample( S) = $35,000

Level of significance α= 1.645

<u> 90% confidence interval</u>

(x^{-} - Z_{\alpha } \frac{s}{\sqrt{n} } , x^{-} + Z_{\alpha } \frac{s}{\sqrt{n} })

(172000 - 1.645 \frac{35000}{\sqrt{49} } , 172000 +1.645 \frac{35000}{\sqrt{49} })

on calculation , we get

(1,63,775 , 1,80,000)

The mean value lies between the 90% of confidence intervals

(1,63,775 , 1,80,000)

4 0
3 years ago
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