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3 years ago

ASAP -WILL MARK BRIANIST

Mathematics

2 answers:

Zarrin [17]3 years ago

4 0

Answer:

20%

Step-by-step explanation:

40-32=8

8/40=20%

This is what I think I hope it helps If right mark me brainliest If wrong tell me and I will figure out another answer.

posledela3 years ago

4 0

Answer:

32 are eaten so we need to eliminate that from the total pieces.

40 - 32 = 8 are not eaten YET

8/40 since there are 8 out of 40(in total) that are not eaten

Now we need to convert 8/40 into a percent which means we multiply by a 100 to get 20%.

Brainliest is appreciated.

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Find a parametric representation for the surface. the part of the plane z = x + 3 that lies inside the cylinder x2 + y2 = 9. (en

Evgesh-ka [11]

The cylinder is a clue to use cylindrical coordinates. Taking $x=3\cos\theta$ and $y=3\sin\theta$ , we then are forced to use $z=3\cos\theta+3$ . So the parameterization of the intersection of the plane and cylinder is

$\mathbf s(\theta)=(3\cos\theta,3\sin\theta,3\cos\theta+3)$

To get the surface, we can introduce a second parameter $r$ that "contracts" the elliptical intersection to a point. The simplest way to do this is to use

$\mathbf s(r,\theta)=(3r\cos\theta,3r\sin\theta,3r\cos\theta+3)$

with $0\le r\le1$ and $0\le\theta\le2\pi$ .

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3 years ago

What is 13.8924439894 rounded to the nearest tenth

gogolik [260]

1st decimal place=tenth
2nd=hundreth

to round, you look at the place after it
so 13.8924439894 to tenth
look untill hundreth
13.89
if hundreth>5, round tenth up
if hundreth place<5 leave tenth as is

13.89
9>5
round up
8+1=9
13.9 is to theh tenth

8 0

3 years ago

Read 2 more answers

What is 1/6 of 42 How to solve it

Ainat [17]

You would just divide it by 6 wich maked is 7

3 0

3 years ago

PLEASE HELP QUICK AND EXPLAIN. I'M OFFERING 25PTS (It's only worth 10pts) AND BRAINLIEST ANSWER. I'VE POSTED LIKE 5 TIMES PLEASE

Vladimir79 [104]

Answer:

A) Graph the points (length is x, weight is y)

B) Find slope and substitute 75 for x value

c) the relationship between length and weight is... (define the slope)

a) draw line through (0,40) and (6,70)

b) First find the slope and put it into y=mx+b (i guess you know this). then put slope into slope int. form and yeah.

c) just put x as 18 and solve for y, monthly revenue.

Step-by-step explanation:

I was too lazy so i just gave instructions in the answer. Follow them and you should be fine. Good Night.

5 0

3 years ago

The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and

brilliants [131]

Answer:

The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

Step-by-step explanation:

The equation of the parabola is:

$y=0.00035x^{2}$

Compute the first order derivative of y as follows:

$y=0.00035x^{2}$

$\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]$

$=2\cdot 0.00035x\\\\=0.0007x$

Now, it is provided that |x | ≤ 605.

⇒ -605 ≤ x ≤ 605

Compute the arc length as follows:

$\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx$

$=\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\$

Now, let

$x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u$

$\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u$

$={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}$

Plug in the solved integrals in Arc Length and solve as follows:

$\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\$

$=1245.253707795227\\\\\approx 1245.25$

Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

7 0

3 years ago