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2 years ago

Its 6 ya'll if you think it no it 6

Mathematics

1 answer:

snow_lady [41]2 years ago

7 0

Answer:

HUH? What do you mean about that?

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Sarah's Shipping and Ryan's Mail Services both ship packages. Sarah's trucks

algol [13]

Answer:I think 11

Step-by-step explanation: 11 because one can do no more than 11 packages so the most potential one most be 11 since it can't do 18 but the 18 can do 11 and the max of the other one is 11

8 0

2 years ago

Select the correct answer.

Black_prince [1.1K]

Answer:

i think the answer is b if i am wrong please tell me please :(

Step-by-step explanation:

6 0

2 years ago

A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 41 specimens and counts the number of

e-lub [12.9K]

Answer:

(53.3; 56.1)

Step-by-step explanation:

Given that:

Sample size, n = 41

Mean, xbar = 54.7

Standard deviation, s = 5.3

Confidence level, Zcritical at 90% = 1.645

Confidence interval :

Xbar ± Margin of error

Margin of Error = Zcritical * s/sqrt(n)

Margin of Error = 1.645 * 5.3/sqrt(41)

Margin of Error = 1.362

Lower boundary = 54.7 - 1.362 = 53.338

Upper boundary = 54.7 + 1.362 = 56.062

(53.3 ; 56.1)

6 0

2 years ago

The three cards below form a number pattern

S_A_V [24]

What three cards I don’t see anything and this is just an statement

4 0

2 years ago

Read 2 more answers

The recursive function LaTeX: f\left(0\right)=1,\:f\left(n\right)=f\left(n-1\right)+2nf ( 0 ) = 1 , f ( n ) = f ( n − 1 ) + 2 n

m_a_m_a [10]

Question:

The recursive function $f(0) = 1$ , $f(n) = f(n-1) + 2n$ represents the nth term of a sequence. Determine the explicit function

Answer:

$f(n) = n^2 + n+1$

Step-by-step explanation:

Given

$f(0) = 1$

$f(n) = f(n-1) + 2n$

Required

Write an explicit formula

Let n = 1

$f(1) = f(1-1) + 2*1$

$f(1) = f(0) + 2$

$f(1) = 1 + 2 = 3$

Let n = 2

$f(2) = f(2-1) + 2*2$

$f(2) = f(1) + 4$

$f(2) = 3 + 4 = 7$

Let n =3

$f(3)=f(3-1) + 2 * 3$

$f(3)=f(2) + 6$

$f(3)=7+ 6 = 13$

Let n = 4

$f(4) = f(4 - 1) + 2 * 4$

$f(4) = f(3) + 8$

$f(4) = 13+ 8 = 21$

So, we have:

$f(1) = 3= 1 + 2 * 1=1+0*1*2*1$

$f(2) = 7= 3 + 2 * 2=1+1*2+2*2$

$f(3) = 13= 7 + 2 * 3= 1+2*3+2*3$

$f(4) = 21 = 13 + 2 * 4= 1+3*4 +2 *4$

Following the above pattern:

$f(n) = 1 + (n - 1) * n + 2 * n$

$f(n) = 1 + n(n - 1) + 2n$

Open bracket

$f(n) = 1 + n^2 - n + 2n$

$f(n) = 1 + n^2 + n$

$f(n) = n^2 + n+1$

3 0

2 years ago