The radius of the circular cross-section of the can of soup is; 3.4cm.
<h3>What is the radius of the can of soup?</h3>
Since, the can has a height of 10cm and the volume of the can is 363cm³, it follows that the area of the circular cross-section can be evaluated as;
A = 363/10 = 36.3cm²
Hence, it follows that the radius can be evaluated as follows;
36.3 = 3.14 × r²
r² = 36.3/3.14
r² = 11.56
r = 3.4cm
Read more on volume of a cylinder;
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17 = p - 3 - 3p
Add 3 to 17.
20 = p - 3p
Combine p and 3p (addition)
20 = -2p
Divide by (-2p) to find p.
Since a negative divided by a negative equals a positive, -p would turn into a positive p.
-10 = p
19+3.5-5 [ Dividing 7 with 2 yields 3.5].
Answer:
360
Step-by-step explanation:
Same as the 1st answer
