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Vlada [557]
3 years ago
11

What is (t)? 0=18000*0.988^t

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0
0=1. The answer is No Solution.
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Difference in the following polynomials (6x^3 - 2x^2 + 4)<br> -(2x^3 + 4x^2 - 5)
Colt1911 [192]

\bold{[ \ Answer \ ]}

\boxed{\bold{4x^3-6x^2+9}}

\bold{[ \ Explanation \ ]}

  • \bold{Find \ Difference: \ \left(6x^3\:-\:2x^2\:+\:4\right)-\left(2x^3\:+\:4x^2\:-\:5\right)}

\bold{-----------------------}

  • \bold{Remove \ Parenthesis}

\bold{6x^3-2x^2+4-\left(2x^3+4x^2-5\right)}

  • \bold{Remove \ Parenthesis \ / \ Simplify}

\bold{-\left(2x^3+4x^2-5\right): \ -2x^3-4x^2+5}

  • \bold{Rewrite}

\bold{6x^3-2x^2+4-2x^3-4x^2+5}

  • \bold{[Simplify \ 6x^3-2x^2+4-2x^3-4x^2+5] \ 4x^3-6x^2+9}

\bold{4x^3-6x^2+9}

\boxed{\bold{[] \ Eclipsed \ []}}

6 0
3 years ago
Ydhdhdgshshsysyhsjdudhdndhdhdbdhdydbwjhswnjshdd​
SVETLANKA909090 [29]

Answer:

ty to the points :>

Step-by-step explanation:

tytytytysm

6 0
2 years ago
Read 2 more answers
Ve the equation. 3c + 1 = c +1​
yKpoI14uk [10]
Subtract C in both sides:
2c + 1 = 1

Subtract 1 on both sides
2c = 0

The solution is:
x = 0

Hope this helped
4 0
3 years ago
Please help on this math question
svetlana [45]

\sqrt{12 {x}^{3} }  =  {12}^{ \frac{1}{2} }  {x}^{ \frac{3}{2} }

6 0
2 years ago
Nadine can send or receive a text message for $0.15 or get an unlimited number for $5.00. Write and solve an inequality to find
pogonyaev
I think it would be 33 1/2 messages.

7 0
3 years ago
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