To find the rate, you must divide the distance traveled by the time it took.
17.5 m is the distance while time it took was 5 seconds.
So,
17.5 ÷ 5 = 3.5 m/s
The rate of the anchor is 3.5 m/s
Note: I did not ignore the negative sign in the distance but rather acknowledged it as a magnitude. This meant that the anchor was dropping down instead of going up.
Not a function, because it does not pass the vertical line test.
Area of a parallelogram = A =base*height
so in this case is just (1½)(6).
first off let's convert the mixed fraction to "improper",
18/8
8/8
1/8 = 0.125
1+0.125=1.125