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aniked [119]
3 years ago
10

What is family and it's importance​

Chemistry
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

<h2><u>FAMILY:</u></h2>

Family is defined as a specific group of people that may be made up of partners, children, parents, aunts, uncles, cousins and grandparents. An example of a family is a set of parents living with their children. The definition of family is the group of people who share common ancestors.

<h2><u>IMPORTANCE:</u></h2>

Family is very important part of our everyday life. It helps us in improving our personality. It also helps us in shaping our life. It teaches us the value of love, affection, care, truthfulness and self-confidence and provides us tools and suggestions which are necessary to get success in life.  Family is a place where you can be yourself. It is a place where you are accepted for what you are. This is where you are completely tension free and everyone is there to help you. Family encourages you when you are surrounded by problems. It helps you survive through tough times and bring joy and happiness into life.

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Calculate the equilibrium concentration of H 3 O H3O in a 0.20 M M solution of oxalic acid. Express your answer to two significa
Black_prince [1.1K]

<u>Answer:</u> The equilibrium concentration of H_3O^+ ion is 8.3064\times 10^{-2}M

<u>Explanation:</u>

We are given:

Molarity of oxalic acid solution = 0.20 M

Oxalic acid (H_2C_2O_4) is a weak acid and will dissociate 2 hydrogen ions.

  • The chemical equation for the first dissociation of oxalic acid follows:

               H_2C_2O_4(aq.)+H_2O\rightleftharpoons H_3O^+(aq.)+HC_2O_4^-(aq.)

<u>Initial:</u>        0.20

<u>At eqllm:</u>    0.20-x                            x                 x

The expression of first equilibrium constant equation follows:

Ka_1=\frac{[H_3O^+][HC_2O_4^{-}]}{[H_2C_2O_4]}

We know that:

Ka_1\text{ for }H_2C_2O_4=0.059

Putting values in above equation, we get:

0.059=\frac{x\times x}{(0.20-x)}\\\\x=-0.142,0.083

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = x = 0.083 M

  • The chemical equation for the second dissociation of oxalic acid:

                 HC_2O_4^-(aq.)+H_2O\rightarrow H_3O^+(aq.)+C_2O_4^{2-}(aq.)

<u>Initial:</u>         0.083  

<u>At eqllm:</u>    0.083-y                      0.083+y               y

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H_3O^+][C_2O_4^{2-}]}{[HC_2O_4^-]}

We know that:

Ka_2\text{ for }H_2C_2O_4=6.4\times 10^{-5}

Putting values in above equation, we get:

6.4\times 10^{-5}=\frac{(0.083+y)\times y}{(0.083-y)}\\\\y=-0.083,0.0000639

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = y = 0.0000639 M

Total concentration of hydronium ion = [x + y] = [0.083 + 0.0000639] = 0.0830639 M

Hence, the equilibrium concentration of H_3O^+ ion is 8.3064\times 10^{-2}M

7 0
3 years ago
A steel cylinder has a pressure of 550 torr at 177 degrees Celsius. What will be the pressure if the temperature is decreased by
Schach [20]

Answer:

P_2=507.7torr

Explanation:

Hello there!

In this case, when we have a gas that is undergoing a change in both pressure and temperature, we utilize the Gay-Lussac's equation as shown below:

\frac{T_2}{P_2}=\frac{T_1}{P_1}

Thus, since we are given the initial pressure and temperature and the final temperature, we can compute the final pressure as shown below:

P_2=\frac{P_1}{T_1}*T_2

So we plug in, by making sure the temperatures are in kelvins, to obtain:

P_2=\frac{550torr}{(117+273)K}*(87+273)K\\\\P_2=507.7torr

Best regards!

8 0
3 years ago
A linear graph with a slope of zero would indicate which of the following?
max2010maxim [7]

As the independent variable changes, the dependent variable never changes.

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Use the reaction N2(g) + 3H2(g) 2NH3(g) to answer the following questions
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Answer:

Explanation:

a ) If N₂(g) and 3H₂(g) is added to the system , 2 moles of additional  ammonia will be produced .

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c ) Keq = [ NH₃ ] ² / [ N₂ ] [ H₂]³

d ) Substituting the given values in the equation ,

Keq = [ 6M ] ² / [ 3M] [ 4M]³

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