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vivado [14]
2 years ago
7

This chemical equation represents a chemical reaction H2SO4 + 2LiOH Li2SO4 + 2H2O which two chemicals are the products of the ch

emical reaction shown?
Chemistry
1 answer:
valkas [14]2 years ago
6 0

Answer:

Lithium sulphate (Li₂SO₄) and water (H₂O

Explanation:

H₂SO₄ + 2LiOH —> Li₂SO₄ + 2H₂O

The equation represented above indicates a neutralization reaction.

A neutralization reaction is a reaction involving acid and base which result in the production of salt and water.

In the equation above,

Reactant:

H₂SO₄ (acid)

LiOH (base)

Product:

Li₂SO₄ (salt)

H₂O (water)

Thus, lithium sulphate (Li₂SO₄) and water (H₂O) are the products of the reaction

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What weight of sodium hydroxide will react with 73 gram of hydrogen chloride gas at NTP to Produce 117.0 gram of Nacl and 36 gra
Wewaii [24]

Let's write the equation

\\ \sf\longmapsto {NaOH\atop ?}+{HCl\atop 73g}\longrightarrow {NaCl\atop 117g}+{H_2O\atop 36g}

According to law of conservation of mass .

  • Mass of products=Mass of reactants

Let required value be x

\\ \sf\longmapsto x+73=117+36

\\ \sf\longmapsto x+73=153

\\ \sf\longmapsto x=153-73

\\ \sf\longmapsto x=80g

8 0
2 years ago
Read 2 more answers
38. Identify the most important types of interparticle forces pres
zhannawk [14.2K]

Answer: im thinking its gonna be d.C2H6 and also

the explanation is on the research i had did before i had answered this question so i really hope this help :)

Explanation:

Ar = van de waals forces or london forces

C

H

4

= van de waals forces or london forces

HCl=permanent dipole-dipole interactions

CO = permanent dipole-dipole interactions

HF = hydrogen bonding

N

a

N

O

3

= permanent dipole-dipole interactions

C

a

C

l

2

= van de waals forces or london forces

4 0
3 years ago
A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128
alisha [4.7K]

Answer: The final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

Explanation:

The given data is as follows.

mass = 7.62 g,           T_{2} = 10.8^{o}C

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

       q = mC \times \Delta T    

          = 7.62 g \times 4.184 J/^{o}C \times (52.3 - T)

Now, heat gained by lead will be calculated as follows.

       q = mC \times \text{Temperature change of lead}  

           = 2.04 \times 0.128 \times (T - 11.0)

According to the given situation,

     Heat lost = Heat gained

7.62 g \times 4.184 J/^{o}C \times (52.3 - T) = 2.04 \times 0.128 \times (T - 11.0)

        T = 50.26^{o}C

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

7 0
3 years ago
Why is it important for scientists to use the scientific method?
shtirl [24]
I believe the answer is A
3 0
3 years ago
What are the three isotopes of hydrogen and what is the significance of these isotopes?
antiseptic1488 [7]

Answer:

21H deuterium (D), 31H is tritium (T), 11H is hydrogen

Explanation:

11H: it has the greatest abundance, it has only one proton (it does not have neutrons).

 21H (D): it has a proton and a neutron in its nucleus.

 31H (T): it has a proton and two neutrons in its nucleus.

Remember that isotopes have the same atomic number, but a different mass number (elements in the number of neutrons differed).

4 0
3 years ago
Read 2 more answers
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