Answer:
That
Step-by-step explanation:
Answer:
option c will make ur answer correct just see 3(-6) + 2(2) = -14
Answer:
At a distance of 525 km from the station both trains meet.
Step-by-step explanation:
Speed of the first train
= 75 ![\frac{m}{hr}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bhr%7D)
Speed of the second train
= 105 ![\frac{m}{hr}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bhr%7D)
Distance traveled by first train in two hours = 75 × 2 = 150 km
When the first train traveled a distance of 150 km than second train starts from the station.
Let suppose the two trains meet after T hours.
Value of T is given by
![T = \frac{D}{S_{1} - S_{2} }](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7BD%7D%7BS_%7B1%7D%20-%20S_%7B2%7D%20%20%20%7D)
Put the value of D &
&
we get
![T = \frac{150}{105 - 75}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B150%7D%7B105%20-%2075%7D)
T = 5 hours
Thus the two trains meet after 5 hours &
⇒ Distance from the station is = Speed of second train × 5
⇒ Distance from the station is = 105 × 5
⇒ Distance from the station is = 525 km
Therefore at a distance of 525 km from the station both trains meet.
-182=2(1+2x)-2
2*1=2
2*2x=4x
-182=4x+2-2
-182=4x
-45.5=x