Answer:
2/7
Step-by-step explanation:
I am assuming that you mean 285714 repeating.
You just have to memorize or learn to recognize the order of decimal digits for fractions over 7, unless you want to do it algebraically.
1/7=0.142857 repeated
2/7=0.285714 repeated and so on
8 x n + 2 = 4
If you could show me a photo I’d probably be able to help more.
Answer:
x° is 66°
Step-by-step explanation:
From the given diagram, we have;
∠JIH = 105° Given
∠IDJ = 39° Given
Therefore, we have;
∠JID and ∠JIH are supplementary angles, by the sum of angles on a straight line
∴ ∠JID + ∠JIH = 180° by definition of supplementary angles
∠JID + 105° = 180° by substitution property
∠JID = 180° - 105° = 75° by angle subtraction postulate
∠JID = 75°
∠IDJ + ∠JID + ∠IJD = 180° by the sum of interior angles of a triangle
∠IJD = 180° - (∠IDJ + ∠JID) = 180° - (39° + 75°) = 66° angle subtraction postulate
∠IJD = 66°
∠x° ≅ ∠IJD, by vertically opposite angles
∴ ∠x° = ∠IJD = 66° by the definition of congruency
∠x° = 66°
Answer: Our required probability is 0.3387.
Step-by-step explanation:
Since we have given that
Number of red cards = 4
Number of black cards = 5
Number of cards drawn = 5
We need to find the probability of getting exactly three black cards.
Probability of getting a black card = 
Probability of getting a red card = 
So, using "Binomial distribution", let X be the number of black cards:

Hence, our required probability is 0.3387.
Answer:
![\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-%5Cfrac%7B8%7D%7B%5Csqrt%7B117%7D%20%7D%20%5C%5C%5Cfrac%7B7%7D%7B%5Csqrt%7B117%7D%20%7D%5C%5C%5Cfrac%7B2%7D%7B%5Csqrt%7B117%7D%20%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
We are required to find a unit vector in the direction of:
![\left[\begin{array}{c}-8\\7\\2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-8%5C%5C7%5C%5C2%5Cend%7Barray%7D%5Cright%5D)
Unit Vector, 
The Modulus of
=
Therefore, the unit vector of the matrix is given as:
![\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-%5Cfrac%7B8%7D%7B%5Csqrt%7B117%7D%20%7D%20%5C%5C%5Cfrac%7B7%7D%7B%5Csqrt%7B117%7D%20%7D%5C%5C%5Cfrac%7B2%7D%7B%5Csqrt%7B117%7D%20%7D%5Cend%7Barray%7D%5Cright%5D)