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victus00 [196]
3 years ago
15

Terrance's garden is 3/ 5 yard by 1 2/ 5 yards. Each square is 1/ 5 yard long. He needs to know the area so he can buy the right

amount of fertilizer. What is the area of his garden?
Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

brain

Step-by-step explanation:

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120 is 15% of what number
son4ous [18]
120 = 15% x

15% = 0.15

x = 120 / 0.15 = 800
6 0
3 years ago
Read 2 more answers
The coordinates of the vertices for rectangle ABCD are A (2,4), B (6,10), C (9,8) and D (5,2). What
sweet [91]

Answer:

D. \sqrt{65}

Step-by-step explanation:

The computation of the  length of a diagonal (AC or BD) of the rectangle is shown below:

As we know that

The Diagonal length of AC is

= (x_2 - x_1)^2 + (y_2 - y_1)^2\\\\= (9 -2)^2 + (8 - 4)^2\\\\= (7)^2 + (4)^2

= \sqrt{49 + 16}\\\\= \sqrt{65}

Therefore correct option is D.

3 0
3 years ago
The table shows conversions for common units of length.
Vedmedyk [2.9K]

Answer:

1 kilometer

0.621371 miles

Step-by-step explanation:

Given data

In the given table we are presented with the conversion table for common units and we are required to present the conversion for kilometers to miles

Hence the conversion from kilometers to miles is presented below

1 kilometer

0.621371 mile

3 0
3 years ago
How do you find the bearing and speed of a ship?
Usimov [2.4K]
Finding the Bearing<span> of a </span>Ship<span> 
Example : A </span>ship<span> leaves the port of Miami with a </span>bearing<span> of S80◦E and a </span>speed<span> of. 15 knots. After 1 hour, the </span>ship<span> turns 90◦ toward the south.</span>
3 0
3 years ago
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
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