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Feliz [49]
3 years ago
15

What element in the domain has image 7 in the function f(x) = x²– 2?a. 3 b) 9 c) -1 d) 4

Mathematics
2 answers:
blagie [28]3 years ago
6 0

Here,

f(x) = 7

x = ?

Now,

f(x) = x^2 - 2

or, 7 = x^2 - 2

or, 7 + 2 = x^2

or, x^2 = 9

◆ x = 3

a) 3

I hope it's help you...

Thanks♥♥

snow_lady [41]3 years ago
6 0

Answer:

f(x) = 7 \\ f(x) =  {x}^{2}  - 2 \\  {x}^{2} - 2 = 7 \\  {x}^{2}   = 2 + 7 \\  {x}^{2}  = 9 \\ x =  \sqrt{9}  \\  \boxed{x = 3}

Therefore, 3 is the element in the domain which has the image 7 in function f(x)=x²-2

  • A. 3 is the right answer.
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Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8
goblinko [34]
\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y  = \frac{17}{14} } \atop {x+7y=8}} \right.

To solve this system by substitution, first isolate x in the second equation.

x+7y=8
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Now, plug this expression (8-7y) for x in the top equation to solve for y.

\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}
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72-63y+8y=17
72-55y=17
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Now that you have y, plug it into the second equation and solve for x.

x+7y=8
x+7(1)=8
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Last step is to plug your x- and y-values in to both equations to check your work.

\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}

\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ;  \frac{1}{3} * \frac{8}{8} = \frac{8}{24}

\frac{9}{24} + \frac{8}{24} = \frac{17}{24}  <--True

1+7(1)=8
1+7=8   <--True

Answer:
x=1 \\ y=1
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