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Mashutka [201]
3 years ago
9

. The area of particle 1 is

Biology
1 answer:
charle [14.2K]3 years ago
7 0

Answer:

The correct answer is - 5 times

Explanation:

Given:

area of P1 = 2.5

area of P2 = 0.5

Solution:

Let assume:

area of P1 is x times of the area of P2

then the equation would be:

=>  2.5 = x*0.5

=>  2.5/0.5 = x

=> 5 = x

Thus, area of P1 is 5 times to the area of P2

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uppose that molecules of glucose are ingested, absorbed into the bloodstream, and then converted inside muscle cells to carbon d
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In the first reaction, the glucose entering the tissues is phosphorylated to the hydroxyl group at C6, with the energy expenditure of an ATP molecule, giving rise to glucose-6-phosphate and ADP. [1] This reaction, catalyzed by the hexokinase enzyme, is irreversible under physiological conditions due to its highly negative ΔG °. It is one of the three steps that regulate glycolysis. The phosphorylation of glucose in the first reaction prevents it from leaving the cell again (glycolysis takes place in the cell's cytosol). By adding a phosphate group to glucose, it becomes a negatively charged molecule and it is impossible to passively pass through the cell membrane, keeping it trapped within the cell.

Glucose-6-phosphate is a branching point in carbohydrate metabolism. It is a precursor to almost all routes that use glucose, including glycolysis, via pentose phosphate and glycogen synthesis. From an opposite point of view, it can also be generated from other carbohydrate metabolism routes, such as glycogenolysis (glycogen breakdown), via pentose phosphate and gluconeogenesis (synthesis of glucose from non-carbohydrates).

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Reaction 2: phosphohexose isomerase

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Phase 2: ATP production and oxidation

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