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3 years ago

13

What is the surface area of a right circular cylindrical oil can, if the radius of its base is 4 inches and its height is 11 inc

hes?
a. 85 pi in.2

b. 100 pi in.2

c. 120 pi in.2

d. 225 pi in.2

2 answers:

Fantom [35]3 years ago

7 0

Answer:

c

Step-by-step explanation:

irakobra [83]3 years ago

6 0

Your answer should be answer b. 100 pi in.2

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What would be the percentage of a multiple times the denominator :example 50/190:)

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To find the percentage, like 50/190, 50÷190 =.2631578947 or simply 26%

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3 years ago

Weekly wages at a certain factory are

Furkat [3]

Answer: 0.1359

Step-by-step explanation:

mean = $400

Standard deviation = $50

Since the wages is normally distributed , the first thing is to find the z - score.

z = $\frac{x-mean}{standard deviation}$

finding the z - value for 300 and 350 , we have

z = $\frac{300-400}{50}$

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2 = -2

also

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z = $\frac{-50}{50}$

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Therefore , the the probability that a worker

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3 years ago

The volume of water and a rectangle swimming pool can be modeled by the function v(x)=x^3+13x-210. If the depth of the pool is g

S_A_V [24]

Answer:

Required,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

Step-by-step explanation:

Given volume and depth respectively,

$V(x)=x^3+13x-210$ and $x-3$

To find length and width of the rectanglular swiming pool we know,

Volume=length $\times$ height $\times$ depth.

Let depth=D=x-3, length=L, width=W, then

$V=DLW$

$x^3+13x-210= LW(x-3)$

$LW=\frac{x^3+13x-210}{x-3}$

After divide we will get $x^2-3x-22$ with remainder -144.

Thus,

$x^3+13x-210=(x^2-3x-22)(x-3)-144=(x-3)LW$

Now to find root of,

$x^2-3x-144=\frac{3\pm\sqrt{9+88}}{2}=\frac{3\pm \sqrt{37}}{2}$

Thus,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

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3 years ago

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grandymaker [24]

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7 0

3 years ago

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