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postnew [5]
3 years ago
15

Find the volume of the figure shown below.

Mathematics
1 answer:
Alex777 [14]3 years ago
3 0
10 cm would stay as a 10 cm
14cm would round down to a 10
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F(x) = 4x - 9 step by step and put the right anwser so I can read it
butalik [34]
<h2>f = -5</h2><h3></h3><h3>f(x) = 4x - 9</h3><h3>Add 9 to both sides</h3><h3>f(x) + 9 = 4x</h3><h3>Divide x from both sides</h3><h3>f + 9 = 4</h3><h3>Subtract 9 from both sides</h3><h3>f = -5</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
7 0
3 years ago
I need help please. If you are correct, I will give you Brainliest.
earnstyle [38]

Answer:

(C) 220

Step-by-step explanation:

Let x represent the number of adult tickets sold and y represent the number of student tickets sold. With the information given, we can set up two equations:

x+y=360

5x+3y=1360 (Since for every adult ticket sold, $5 is made and for every student ticket sold, $3 is made)

In the first equation, we can represent x in terms of y:

x=360-y

And then, we can substitute x in the second equation for 360 - y to get:

5(360-y)+3y=1360 which simplifies to:

1800-2y=1360 and therefore, y=220.

Hope this helps :)

5 0
3 years ago
True or False? The graph of sine can be used to construct the graph of the secant function.
amid [387]

True

Note that:

secant \theta = \frac{1}{cos\theta}

The graph of sine and cosine functions are very similar. They only have a shift in the x -axis.

That is,  sin x  =  cos (90  -  x)

Since there is a great similarity between the sine and cosine graphs, and the secant graph is an inverse of the cosine graph, the graph of sine can be used to construct the graph of the secant function

Mathematically:

since  sec x  =  1 / cos x

and, cos x = sin (90 - x)

therefore, sec x = 1 / sin (90 - x)

The graphs of the sine and secant functions are attached to this solution

Learn more here: brainly.com/question/9554579

5 0
3 years ago
It's the 2nd question I know how it is done ....sum and product method but the root is confusing me can any one explain me plz
weeeeeb [17]
Hey,
2x^2 + 3root5x + 5
Here the product=10
And,sum=3root5
=>2x^2+2root5x+root5x+5
=>2x(x+root5)+ root5(x+root5)
=>(2x+root5)(x+root 5)

8 0
3 years ago
2x-y=5<br>2x-2y=4<br><img src="https://tex.z-dn.net/?f=2%20%5Ctimes%20%20-%20y%20%3D%205%20%5C%5C%202%20%5Ctimes%20%20-%202y%20%
d1i1m1o1n [39]
\left\{\begin{array}{ccc}2x-y=5\\2x-2y=4&|\cdot(-1)\end{array}\right\\\underline{-\left\{\begin{array}{ccc}2x-y=5\\-2x+2y=-4\end{array}\right}\ \ \ \ |add\ both\ sides\\.\ \ \ \ \ \ \ \ y=1\\\\substitute\ the\ value\ of\ y\ to\ first\ equation\\\\2x-1=5\ \ \ |+1\\2x=6\ \ \ |:2\\x=3\\\\\left\{\begin{array}{ccc}x=3\\y=1\end{array}\right
7 0
3 years ago
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