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Ira Lisetskai [31]
2 years ago
9

What methods do you know that can be used to solve a quadratic equation?

Mathematics
2 answers:
zhuklara [117]2 years ago
8 0

Answer: If the quadratic equation has real, rational solutions, the quickest way to solve it is often to factorise into the form (px + q)(mx + n), where m, n, p and q are integers. This is especially true where the coefficient of x2 is 1.

Example 1 - Solve x2+7x+12=0

Step-by-step explanation:

that's the only one I remember

stepan [7]2 years ago
7 0

Answer:

factoring, using the square roots, completing the square and the quadratic formula.

Step-by-step explanation:

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\bf \textit{difference of squares}
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(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
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\textit{also recall that }i^2=-1\\\\
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\begin{cases}
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3 years ago
Glenda receives a salary of $4,792 bimonthly. Find Glenda’s earnings per year.
Andre45 [30]

Answer: $28,752

Explanation:

The<u> definition of bimonthly</u> is an event that happens once in two months. -bi represents "two", while -monthly represents "event that happens by month.

Given that Glenda receives a salary of <u>$4,792 bi-monthly</u>, we are required to find the earnings per year.

There are <u>12 months in each year</u>, and if the given value is a 2-month value, then we shall divide 12 by 2 to find that there is in total 6 of the 2-month value.

12/2=6

Finally, we shall <u>multiply the total number with the salary</u>, which will be $4,792 times 6.

4792*6=\boxed{28752}

Hope this helps!! :)

Please let me know if you have any questions

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