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Marina CMI [18]
2 years ago
7

PLZ HELP FAST ASAP I NEED HELP RIGHT NOW TODAY PLZ! VERY APPRECIATE

Mathematics
1 answer:
NemiM [27]2 years ago
4 0

Answer:

Find the relative frequency for the event ​"heads​" for each friend:

Friend 1: 0.59 (41/70)

Friend 2: 0.7 (49/70)

Friend 3: 0.37 (26/70)

If the friends combine their results to get 116 heads and 94 ​tails, what is the relative frequency for the event ​"heads​"?

0.55 (116/210)

Suppose each friend flips a coin 700 times. Is there a value you would expect the relative frequency for the event ​"​heads" to be close​ to?

For Friend 1, basing it off the 0.59 frequency from earlier, I would expect the heads to be around 413.

Friend 2, 490

Friend 3, 259

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Answer:

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Step-by-step explanation:

Giving the following information:

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. In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one stu
Sergeeva-Olga [200]

Answer: B. H_0:p_1=p_2

H_a:p_1>p_2

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Objective for the study : Whether the proportion of U.S. adults that smoke declined during the 5-year period between the samples.

i.e. p_1>p_2

Alternative hypothesis(H_a) is the statement containing population  parameter that shows there is significant difference between the groups being tested.

⇒ H_a:p_1>p_2

Null hypothesis(H_0) is the statement containing population parameter that shows there is no significant difference between the groups being tested.

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Hence, The hypotheses to test in this problem are

H_0:p_1=p_2

H_a:p_1>p_2

Hence, the correct answer is B. H_0:p_1=p_2

H_a:p_1>p_2

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