Answer:
Step-by-step explanation:
You haven't attached any graphs but as there area 3 distinct roots the graph will have 2 loops.
Also the end behaviour will be rising from the left negative values of f(x) and at the right it will rise to positive f(x).
I'd start by writing an equation for each of the right triangles. (Pythagorean theorem)
y² + 9² = z²
x² + z² = (4+9)²
4² + y² = x²
we want to find z so combine the equations by substituting the other variables x,y out.
substitute y² for (x² - 4²) in 1st equation.
(x² - 4²) + 9² = z²
now by rearranging the 2nd equation we can substitute x² for (13² - z²)
(13² - z²) - 4² + 9² = z²
169 - z² - 16 + 81 = z²
234 - z² = z²
234 = 2z²
234/2 = z²
117 = z²
√(117) = z
√(9*13) = z
3√(13) = z
13 goes in the box
The ordered pair which makes both inequalities true is (-2, 2).
It is given that inequalities are
y < -x + 1 and y > x
For y < -x + 1
Substituting every ordered pair,
1) (-3, 5)
⇒ 5 < - (-3) + 1
⇒ 5 < 3 + 1
⇒ 5 < 4 is false
2) (-2, 2)
⇒ 2 < -(-2) + 1
⇒ 2 < 2 + 1
⇒ 2 < 3 is true
3) (-1, -3)
⇒ -3 < - (-1) + 1
⇒ -3 < 1 + 1
⇒ -3 < 2 is true
4) (0, -1)
⇒ -1 < -0 + 1
⇒ -1 < 1 is true
Now , for y > x
1) (-3, 5)
⇒ 5 > -3 is true
2) (-2, 2)
⇒ 2 > -2 is true
3) (-1, -3)
⇒ -3 > -1 is false
4) (0, -1)
⇒ -1 > 0 is false
Therefore ,the ordered pair which makes both inequalities true is (-2, 2).
To know more about Inequalities here
brainly.com/question/11612965
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