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andreev551 [17]
3 years ago
10

a block is pulled 0.90m to the right in 2.4s what is the blocks average speed to the nearest hundredths of m/s

Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

0.38\:\mathrm{m/s}

Step-by-step explanation:

Average velocity is given by v=\frac{\Delta x}{\Delta t}, where \Delta x is displacement and \Delta t is change in time.

What we know:

  • \Delta x is 0.90\:\mathrm{m}
  • \Delta t is 2.4\:\mathrm{s}

Solving for v:

v=\frac{0.90}{2.4}=0.375\approx\boxed{0.38\:\mathrm{m/s}}

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xenn [34]

Answer:

Option d. 1 in: 12 ft.

Step-by-step explanation:

A scale model of building is 2 inches tall. If the building is 24 feet tall then we have to find the scale of the model.

Since scale of the model is represented by the ratio of size of scale model and size of original building

Scale factor=\frac{\text{Height of scale}}{\text{Height of building}}

                          = \frac{2}{24}

                          =  \frac{1}{12}

Therefore, Scale of the model is 1 inch : 12 ft.

8 0
3 years ago
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A cone and a cylinder have the same height and their bases are congruent circles
sveticcg [70]

Answer:

30 cm^3

Step-by-step explanation:

Given

radius for both shape = r

height  for both shape = h

volume of cylinder is given by \pi r^2h

volume of cone is given by 1/3(\pi r^2h)

From above two equation we can see that  \pi r^2h is volume of cylinder

thus we can say that volume of cone is 1/3(volume of cylinder)

So we can say that for any cylinder and cone whose height is same and base is congruent

volume of cone will be one-third of volume of cylinder.

Now in given problem

volume of cylinder is 90 cm^3

So , volume of given cone will be one-third of 90 cm^3

which is 1/3*90 cm^3 = 30 cm^3.

Thus, volume of the given cone is 30 cm^3.

Please mark it the brainliest

5 0
3 years ago
Solve x^2 - (7 -1)x + (18 - i) =0
Mazyrski [523]

Step-by-step explanation:

6 0
3 years ago
I need a little help because i forgot how to do this<br><br><br><br>simplify. y^2y^3​
sashaice [31]
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3 years ago
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For a circle with a diameter of 6 meters, what is the measurement of a central angle (in degrees) subtended by an arc with a len
Sholpan [36]

Answer:

\boxed{\boxed{\theta=150^{\circ}}}

Step-by-step explanation:

We know that,

\text{Arc length}=r\cdot \theta

where,

r = radius,

θ = central angle in radian.

Given,

diameter = 6 m, so radius = 3 m.

\text{Arc length}=\dfrac{5}{2}\pi

Putting the values,

\Rightarrow \dfrac{5}{2}\pi=3\theta

\Rightarrow \theta=\dfrac{5}{2\times 3}\pi

\Rightarrow \theta=\dfrac{5}{6}\pi=\dfrac{5}{6}\times 180^{\circ}=150^{\circ}


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3 years ago
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