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3 years ago

a block is pulled 0.90m to the right in 2.4s what is the blocks average speed to the nearest hundredths of m/s

Mathematics

1 answer:

hichkok12 [17]3 years ago

5 0

Answer:

$0.38\:\mathrm{m/s}$

Step-by-step explanation:

Average velocity is given by $v=\frac{\Delta x}{\Delta t}$ , where $\Delta x$ is displacement and $\Delta t$ is change in time.

What we know:

$\Delta x$ is $0.90\:\mathrm{m}$
$\Delta t$ is $2.4\:\mathrm{s}$

Solving for $v$ :

$v=\frac{0.90}{2.4}=0.375\approx\boxed{0.38\:\mathrm{m/s}}$

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3 years ago

In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the

oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation(which is the square root of the variance) $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

$\mu = 503, \sigma = \sqrt{9604} = 98$

$Z = \frac{X - \mu}{\sigma}$

$1.476 = \frac{X - 503}{98}$

$X - 503 = 1.476*98$

$X = 648$

Abby's score

She scored 648.

$\mu = 521 \sigma = \sqrt{10201} = 101$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{648 - 521}{101}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

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2 years ago

A circle has a center of (5,-5) and goes through (6,-2). What is the radius?

azamat

Let O(5, -5) be the center of the circle, and P(6, -2) be a point on this circle.

The distance between points O and P, that is |OP|, is the radius of this circle,

We use the distance between 2 points formula:

|OP|= $\sqrt{ (x_2-x_1)^{2} + (y_2-y_1)^{2} }= \sqrt{ (6-5)^{2} + (-2-(-5))^{2} }$
$= \sqrt{ 1^{2}+ (-2+5)^{2}} = \sqrt{1+9}= \sqrt{10}$ (units)

Answer: $\sqrt{10}$ units

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