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rosijanka [135]
3 years ago
10

. Fiona has $1.20 with which to buy some ribbon.The ribbon is on sale for $0.08 per foot.How many feet of ribbon can Fiona buy

Mathematics
1 answer:
gogolik [260]3 years ago
8 0

Respuesta: 4.5 pies que puede comprar si tiene $ 11.25

Explicación paso a paso:

Dado que hemos dado que

Costo de los dulces por pie = $ 2.50

Dinero total que gastó en dulces = $ 11.25

Sea x el número de pies que puede comprar

Ahora, según la pregunta, obtenemos eso,

Entonces, 4.5 pies que puede comprar si tiene $ 11.25.

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Use the distance formula to find distance between two points. Need help on this ASAP.
astra-53 [7]

Answer:

a) 20 units

b) 2 √10 units

c) 2 √17 units

Step-by-step explanation:

The distance formula is;

D = √(y2-y1)^2 + (x2-x1)^2

a) D = √(-7-9)^2 + (-7-5)^2

D = √256 + 144

D = √400

D = 20

b) D = √(10-8)^2 + (9-2)^2

D = √(2)^2 + 6^2

D = √4 + 36)

D = √40

D = 2 √10 units

c) D = √(1 + 7)^2 + (-8+10)^2

D = √(64 + 4)

D = √68

D = 2 √17 units

3 0
3 years ago
4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
1 year ago
hey these are my grades and this weekend is the end of the school year I just need advice on getting my grades up​
scZoUnD [109]

Answer:

i dont  know much just do ur work correctly

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How many pairs of whole numbers have a sum of 40
Alex
For the writer, <span><span>there are 20
1.       </span>1 + 39 = 40</span> <span><span>
2.       </span>2 + 38 = 40</span>
<span><span>3.       </span>3 + 37 = 40</span>
<span><span>4.       </span>4 + 36 = 40</span> <span><span>
5.       </span>5 + 35 = 40</span> <span><span>
6.       </span>6 + 34 = 40</span>
<span><span>7.       </span>7 + 33 = 40</span>
<span><span>8.       </span>8 + 32 = 40</span> <span><span>
9.       </span>9 + 31 = 40</span>
<span><span>10.   </span>10 + 30 = 40</span> <span><span>
11.   </span>11 + 29 = 40</span> <span><span>
12.   </span>12 + 28 = 40</span>
<span><span>13.   </span>13 + 27 = 40</span> <span><span>
14.   </span>14 + 26 = 40</span> <span><span>
15.   </span>15 + 25 = 40</span> <span><span>
16.   </span>16 + 24 = 40</span> <span><span>
17.   </span>17 + 23 = 40</span> <span><span>
18.   </span>18 + 22 = 40</span> <span><span>
19.   </span>19 + 21 = 40</span> <span><span>
20.   </span>20 + 20 = 40</span>



5 0
3 years ago
What do you notice about the table inputs for the graph of √x?
Airida [17]

Answer:

See below

Step-by-step explanation:

When we talk about the function f(x)=\sqrt{x}, the domain and codomain are generally defaulted to be subsets of the Real set. Once $f:[0,\infty)\to [0,\infty)$ and  $f\subseteq [0,\infty)\times [0,\infty)$ such that $(x,y_1)\in f\wedge(x,y_2)\in f \Rightarrow y_1=y_2$  for $f(x)=\sqrt x$. Therefore,

\[\sqrt{\cdot}: \mathbb R_{\geq 0} \to \mathbb R_{\geq 0} \]

\[x \mapsto \sqrt{x}\]

But this table just shows the perfect square solutions.

4 0
2 years ago
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