Answer:
1.76 x 10⁴ gallons
Step-by-step explanation:
8.2 x 10³ + 9.4 x 10³ = 17.6 x 10³
Although correct 17.6 x 10³ is not in scientific notation
which is
1.76 x 10⁴ gallons
Answer:
The volume of the cone is:
- <u>112.6 cubic inches.</u>
Step-by-step explanation:
You should know that the volume of a straight circular cone is equal to:
- Cone volume = (1/3) PI * r ^ 2 * h
Where:
<em>r = radius.
</em>
<em>h = height.
</em>
Since the radius and diameter are not provided in the exercise but the circumference, the circumference formula should be used and the diameter must be cleared:
- Circumference = PI * Diameter.
When clearing you get:
- Diameter = circumference / PI
By replacing the data you get:
- Diameter = 15 inches / PI
- Diameter = 4.77 inches.
Since the radius is equal to half the diameter, then the diameter is equal to 2,385 inches, now having the value of radius we proceed to replace in the volume formula:
- Cone volume = (1/3) PI * 2.385 in^2 * 18.9 in
- Cone volume = 112.581541 in^3
- <u>Cone volume = 112.6 in^3</u>
Answer:
hope this helps, happy learning!!!
For this problem you'll get a number, find it's opposite and sum 96 to it. The equation used will be:
x = -x + 96
Where:
x = a number
-x = the opposite of x
So:
x = -x + 96
x + x = 96
2x = 96
x = 96 / 2
x = 48
And now, if you do the sum to prove your answer:
48 - 96 = -48
Answer:
Hope it helped,
BioTeacher101
Well assuming you are not talking about blank holidays there are 22 pure year that you get off. Minus one for the fourth of July would be 21. There are 52 Sundays in a year (as there are 52 weeks in a year), with the slight possibility of a 53 Sunday. I'm going to assume that one wouldn't count though since it occurs every six years (hence leap years).
52+21=73
73 x 17.4 = 1,270.2
1,270.2 x 9 = 11,431.8
11,431.8 dollars yearly.
But to answer your question, there is no real way to answer it because I can't assume you participate in every holiday therefor a "bi-weekly" answer is unpredictable. Sorry I couldn't help you all the way but maybe this will give you a start :)
