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It depends on which type of graph you want, but here's one:
so first you might want some square paper, then draw axis (x and y). then you can put measurements on it.
2
1
-4 -3 -2 -1 0 1 2 3 4
-1
-2
and so on
so first you might want some square paper, then draw axis (x and y). then you can put measurements on it.
2
1
-4 -3 -2 -1 0 1 2 3 4
-1
-2
and so on
Step-by-step explanation:
Given the linear equation, y = ⅔x + 1, where the <u>slope</u>, m = ⅔, and the y-intercept, (0, 1) where<em> b</em> = 1.
<h3><u>Start at the y-intercept:</u></h3>In order to graph the given linear equation, start by plotting the coordinates of the y-intercept, (0, 1). As we know, the <u>y-intercept</u> is the point on the graph where it crosses the y-axis. It coordinates are (0, <em>b</em>), for which the value of b represents the value of the y-intercept in slope-intercept form, y = mx + b.
<h3><u>Plot other points using the slope:</u></h3>From the y-intercept, (0, 1), we must use the slope, m = ⅔ (<em>rise</em> 2, <em>run</em> 3) to plot the other points on the graph. Continue the process until you have sufficient amount of plotted points on the graph that you could connect a line with.
Attached is a screenshot of the graphed linear equestion, which demonstrates how I plotted the other points on the graph using the "rise/run" techniques" discussed in the previous section of this post.
