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ale4655 [162]
3 years ago
15

For the years between 2003 and 2010, the equation yˆ=937.98x+12,764.90 models the average cost of tuition of four-year colleges,

in dollars, where x is the number of years after 2000. What is the best estimate for the average cost of tuition in 2005? Enter your answer in the box. Round to the nearest dollar.
Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

The best estimate for the average tuition cost in the year 2005 is $7,455

Step-by-step explanation:

In this question, we shall be using the predicted equation to predict the value of tuition in the year 2005.

The equation is y = 937.98x + 12,764.90

since x is the number of years after 2000 and we are looking at the average tuition cost in year 2005, thus, our x will be 2005-2000 = 5 years

Substituting this into the equation, we have;

y= 937.98(5) + 12,764.90

y = 7,454.8 which is 7,455 to the nearest dollars

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Find the cotangent, cosine, and tangent of both angles A and B.
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Answer:

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Step-by-step explanation:

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ \\ \\ \frac{10}{24} = cot∠B → \frac{5}{12} = cot∠B \\ \frac{24}{10} = cot∠A → 2\frac{2}{5} = cot∠A \\ \\ \frac{24}{10} = tan∠B → 2\frac{2}{5} = tan∠B \\ \frac{10}{24} = tan∠A → \frac{5}{12} = tan∠A \\ \\ \frac{10}{26} = cos∠B → \frac{5}{13} = cos∠B \\ \frac{24}{26} = cos∠A → \frac{12}{13} = cos∠A

I am joyous to assist you anytime.

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