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ale4655 [162]
2 years ago
15

For the years between 2003 and 2010, the equation yˆ=937.98x+12,764.90 models the average cost of tuition of four-year colleges,

in dollars, where x is the number of years after 2000. What is the best estimate for the average cost of tuition in 2005? Enter your answer in the box. Round to the nearest dollar.
Mathematics
1 answer:
VMariaS [17]2 years ago
4 0

Answer:

The best estimate for the average tuition cost in the year 2005 is $7,455

Step-by-step explanation:

In this question, we shall be using the predicted equation to predict the value of tuition in the year 2005.

The equation is y = 937.98x + 12,764.90

since x is the number of years after 2000 and we are looking at the average tuition cost in year 2005, thus, our x will be 2005-2000 = 5 years

Substituting this into the equation, we have;

y= 937.98(5) + 12,764.90

y = 7,454.8 which is 7,455 to the nearest dollars

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3241004551 [841]

Answer:

18=x*.20

15=x*.25

12=x*.30

24=x*.40

39=x*.60

78=x*.30

Step-by-step explanation:

To solve for x on each, divide the number on the left of the equal side by the number x is being multiplied by.  For example, 18/.20=x

5 0
2 years ago
Read 2 more answers
Drag each tile to the correct box. not all tiles will be used.Chris plans to mulch the border surrounding a rectangular garden i
amm1812

Length (L): 2w + 3

width (w): w

border (b): \frac{1}{4} w

Area (A) = (L + b) * (w + b)   <em>NOTE: This is assuming the width also has a border</em>

              = (2w + 3 + \frac{1}{4} w) * (w + \frac{1}{4} w)

              = (2\frac{1}{4} w + 3)(1\frac{1}{4} w)

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5 0
3 years ago
Please help
ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0
2 years ago
Y equals 8<br> X equals 575<br><br> Solve for slope intercept <br><br> y equals mx + b
zhannawk [14.2K]

y = 8

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We want to solve for b in the slope-intercept form y = mx + b.

To complete this problem, we need the value of m, the slope. If you know m, then just plug into y = mx + b this way:

8 = 575m + b

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2 years ago
Pls pls help it is due todayyy
Pani-rosa [81]

Answer:

I did this today and its H

Step-by-step explanation:

Please lmk if im wrong, but im sure its right but js ;)

6 0
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