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ArbitrLikvidat [17]
3 years ago
12

Round this to the nearest hundredth place please!!!

Mathematics
1 answer:
Radda [10]3 years ago
7 0
The number estimated to the nearest hundredths is 6385.62
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Plzzzz due in a few mins help
Eduardwww [97]

Answer:

equation: 4x+6=9

x=0.75

Step-by-step explanation:

4x+6=9

subtract 6 from both sides

4x+6-6=9-6

4x=3

divide by 4 on both sides

4x÷4=3÷4

x=0.75

I hope this is good enough:

6 0
3 years ago
Read 2 more answers
A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confid
katrin [286]

Answer:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 865, \pi = \frac{408}{865} = 0.4717

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 - 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.4384

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 + 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.5050

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

6 0
3 years ago
Whats 2+2? please help i literally dont know
UkoKoshka [18]

Answer:

2 + 2 = 4

Step-by-step explanation:

 

8 0
3 years ago
I am 21 years old my father is 3 times my age how old eill i be when my father is 40
DENIUS [597]

Answer:

Well the answer is 13.3 so 13 years old

Step-by-step explanation:

(F,Y) = (63,21)

Y3=F so F/3=y

so

F= 40

Y=?

40/3=Y

40/3=13.3

4 0
3 years ago
Read 2 more answers
I need help with math
tatuchka [14]
Tell me the problems and i may be able to help

5 0
3 years ago
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