Imagine there are 4 sits for fill for the debate team
we can fill the first sit in 35 different ways, second sit we only have 34 choices , third sit 33 and last sit 32 ways to possible fill it.
35·34·33·32=1,256,640 possible ways the team could be form
Step-by-step explanation:
(x²-1)(x+1)≥0
As it has two multiples,
Therefore,
Either,
x²-1≥0
x²≥0+1
x²≥1
x≤√1
x≤1
Or,
x+1≥0
x≥-1
The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic
pishuonlain [190]
The five-number summary and the interquartile range for the data set are given as follows:
- Interquartile range: 50 - 29 = 21.
<h3>What are the median and the quartiles of a data-set?</h3>
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
- The interquartile range is the difference between the third quartile and the first quartile.
In this problem, we have that:
- The minimum value is the smallest value, of 24.
- The maximum value is the smallest value, of 56.
- Since the data-set has odd cardinality, the median is the middle element, that is, the 7th element, as (13 + 1)/2 = 7, hence the median is of 43.
- The first quartile is the median of the six elements of the first half, that is, the mean of the third and fourth elements, mean of 29 and 29, hence 29.
- The third quartile is the median of the six elements of the second half, that is, the mean of the third and fourth elements of the second half, mean of 49 and 51, hence 50.
- The interquartile range is of 50 - 29 = 21.
More can be learned about five number summaries at brainly.com/question/17110151
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Given
Rob is twice Joshua's age
Nick is 5 years older than Joshua.
sum of all their ages is 45.
Find the age of nick.
To proof
As given
Rob is twice Joshua's age
let Joshua's age = x
than Rob age = 2x
Nick is 5 years older than Joshua.
Nick age = 5 + x
sum of all their ages is 45
than the equation becomes
Joshua's age + Rob age + Nick age = 45
put the value
x + 2x + 5 + x = 45
4x = 40
x = 10
Joshua's age = 10 year
than Rob age = 20 year
Nick age = 5 + 10
= 15year
Hence proved
