Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Answer:
The percentage error of measurement is 5.63 %
Step-by-step explanation:
Given as :
The measure length of the fence = 150 feet
The actual length of the fence = 142 feet
Let the percentage error in measurement = x
So, x =
×100
Or, x =
×100
or, x =
×100
or, x = 5.63 %
Hence The percentage error of measurement is 5.63 % Answer
Answer: D: the point (0,0) contains the x-intercept
Step-by-step explanation:
15 sandwiches
3 tomatoes= 5 sandwiches.
So if there's 9, that makes 3 groups of 3 tomatoes which would make 3x5 or 5+5+5 ;-;
15.
Answer:
c=18.34
Step-by-step explanation: