Considering the least common factor of 15 and 18, it is found that they will depart from the central station at the same time at 11 AM.
<h3>How to find the time it takes for periodic events to repeat at the same time?</h3>
To find the time that passes between the events happening at the same time, we need to find the least common multiple of the periods.
In this problem, the periods are of 15 and 18, hence their lcm is found as follows:
15 - 18|2
15 - 9|3
5 - 3|3
5 - 1|5
1 - 1
Hence:
lcm(15,18) = 2 x 3 x 3 x 5 = 90 minutes.
They will depart from the central station at the same time in 90 minutes from 9:30 AM, hence at 11 AM.
More can be learned about the least common factor at brainly.com/question/16314496
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Note: On the unit circle, P (x, y) = (cos(t), sint(t))
Terminal point of t = 10pi/3 is <span>( -1/2, -sqrt(3)/2)</span>
Step-by-step explanation:
You need to solve for x.
You can do that by either setting both of the equations equal to each other. or Solve each one separately and subtract the EG equation from the EW to get GW
Answer:
Null hypothesis is rejected. Standard deviation is > 8 miles per hour
Step-by-step explanation:
σ [Population standard deviation] = 8 , s [sample standard deviation] = s
n [no of items] = 8
H0 [Null] : σ = 8 ; H1 [Alternate - Right Tail] : σ > 8
χ2 = (n - 1) . s^2 / σ^2
= 49 x (10.5)^2 / 82 = 5402.25 / 64
χ2 = 84.410
df [degree of freedom] = n -1 = 50 - 1 = 49
P value (χ^2 49 > 84.410) = 0.00125
p = 0.0013
p < α ie 0.05
So, H0 is rejected
Hence we state that standard deviation is > 8 miles per hpur