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Vladimir [108]
3 years ago
12

Water and oil are mixed in the ratio 3:5. Find the density of the mixture if the density of water is 1g/cm ^3 and that of oil is

0.8g/cm^3
Mathematics
1 answer:
kompoz [17]3 years ago
8 0

Answer:

Density of mixture is 7.0 g/cm^{3}.

Step-by-step explanation:

Density of mixture = density of water in the mixture + density of oil in the mixture

Given: water and oil were mixed in a ratio 3:5

           density of water is 1.0 g/cm^{3} and that of oil is 0.8 g/cm^{3}.

Then,

density of water in the mixture = 3 x 1.0 g/cm^{3}

                                   = 3.0 g/cm^{3}

Density of the volume of water in the mixture is 3.0 g/cm^{3}.

density of oil in the mixture = 5 x 0.8 g/cm^{3}

                                              = 4.0 g/cm^{3}

Density of oil in the mixture is 3.0  g/cm^{3}.

So that,

Density of mixture = 3.0 + 4.0

                               = 7.0

Density of mixture is 7.0 g/cm^{3}.

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jek_recluse [69]

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Step-by-step explanation:

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The first step is to find the area of both bases like this:

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The second step is to get the lateral area, which is compound of three rectangles, hence the process is the following:

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