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Thepotemich [5.8K]
2 years ago
11

Why do we not use a Leg-Leg (LL) Theorem that says if you know that the legs of two right triangles are congruent, then the tria

ngles are congruent?
A. This information is not sufficient to prove triangles congruent.
B. This case is already covered by the HL Theorem.
C. This case is already covered by the SSS Postulate.
D. This case is already covered by the SAS Postulate.
Mathematics
1 answer:
Svet_ta [14]2 years ago
6 0
It’s c I think but correct me if I’m wrong
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What is the total amount of 2/5+5/3+9/3 and the lowest common denominator?
gregori [183]

The lowest common denominator is lcm(5, 3), which is 15.

The sum of 2/5 + 5/3 + 9/3 is 6/15 + 25/15 + 45/15, which is 76/15 or 5\frac{1}{15}.

4 0
3 years ago
The quotient of three and the quantity of three less than one-sixth of a number x?
UkoKoshka [18]
\frac{3}{\frac{x}{6}-3}=\frac{3}{\frac{x-18}{6}}=3*\frac{6}{x-18}=\frac{18}{x-18}
Good, right?
7 0
3 years ago
If 5 slices of pizza cost $5:50 how much does 
kupik [55]

The first thing we must do for this case is to define variables.

We have then:

x: number of slices

y: total cost

We write the linear function that relates the variables.

We have then:

y = (\frac{5.50}{5}) * x

Then, we evaluate the number of slices to find the total cost.

-two slices cost:

We substitute x = 2 in the given equation:

y = (\frac{5.50}{5}) * 2\\y = 2.2

Answer:

two slices = 2.2 $

-ten slices cost:

We substitute x = 10 in the given equation:

y = (\frac{5.50}{5}) * 10\\y = 11

Answer:

ten slices = 11 $

-half a slice cost:

We substitute x = 1/2 in the given equation:

y = (\frac{5.50}{5}) * \frac{1}{2}\\y = 0.55

Answer:

half a slice = 0.55 $

6 0
2 years ago
How do you round money to the nearest cent?Like for ex.:$2.15 to the nearest cent
Digiron [165]


To round money to the nearest cent you would see in the ones place what that number is and if it is at or higher than 5 it would round up to 2.20               

Did that help any I hope so:) if not tell me I will have another strategy

7 0
2 years ago
Juan owns 7 pairs of pants, 3 shirts, 5 ties, and 6 jackets. How many different outfits can he wear to school if he must wear on
ZanzabumX [31]

To solve this problem, just use multiplication.

7\text{ pairs of pants}*3\text{ shirts}*5\text{ ties}*6\text{ jackets}=\large\boxed{630\text{ outfits}}

You can somewhat think of this situation as a sort of tree. You start with 7 large branches representing the pants, then for every one of those you have 3 medium-sized branches to represent the pairs of pants. Each one of those has 5 sticks for the ties, which in turn each have 6 leaves to represent the jackets and therefore a complete outfit. The solution is found by getting the total number of leaves on the tree.

8 0
2 years ago
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