First, we need to divide by 20 to find one team.
this means that one team has 9 students. The unit rate is
The following are equivalent:
8-10x + 6
8-(10x-6)
-10x+14
In this circle we have major arc RQ which is the really big one measuring 40x, and we have minor arc RQ, which is what we are looking for. Minor arc RQ is double the measure of the angle that intercepts it. That means that minor arc RQ is 2(12x-12), which is 24x - 24. The measure of the outside of any circle will always and forever be 360 degrees; therefore, 40x + 24x - 24 = 360. Combining like terms gives us 64x = 384 and x = 6. Now sub in that 6 for the x in the angle 12x - 12 to get that that angle measures 12(6)-12 = 60. Again, the angle is half the measure of the arc it intercepts, so minor arc RQ is 120 degrees, third choice down.
Answer:
230 5/9
Step-by-step explanation:
after adding tou would get 230 5/9
6>4-2x<4
so therefor (4x-2) must be less than 6 and less than 4
it must be
6>4-2x and 4<4-2x
find the intersection
6>4-2x
add 2x to both sides
6+2x>4
subtract 6
2x>-2
divide by 2
x>-1
4>4-2x
add 2x
4+2x>4
subtract 4
2x>0
x>0
so we have
x>0
and x>-1
the range of x>-1 includes most of x>0 so the answer is
x>-1
