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sammy [17]
3 years ago
12

Please help me bro please

Mathematics
2 answers:
GaryK [48]3 years ago
6 0

Answer:

  • n = 11°

⠀

Step-by-step explanation:

  • When two straight lines intersect each other, then the pairs of angles so formed without any common arm are called vertically opposite angles.

  • Vertically opposite angles are equal to each other.

⠀

So,

{\longrightarrow \it\qquad { \ { (6n   - 4) {}^{ \circ}   =  {(5n + 7)}^{ \circ} }}}

⠀

Removing the brackets,

{\longrightarrow \it\qquad { \ { 6n   - 4{}^{ \circ}   =  {5n + 7 \: }^{ \circ} }}}

{\longrightarrow \it\qquad { \ { 6n   - 5n   =  {  7 \: }^{ \circ} +4{}^{ \circ} }}}

{\longrightarrow \it\qquad { \pmb{ n   =  {  11 \: }^{ \circ}  }}}

⠀

Therefore,

  • The value of n is 11°
Marianna [84]3 years ago
4 0

We will use the <em>concept</em> of Vertically Opposite angle here, i.e at the <em>point</em> of Intersection of two straight lines, the VOA (Vertically Opposite Angles) are <em>equal</em>

By using this property we will be <em>having</em> ;

{:\implies \quad \sf (6n-4)^{\circ}=(5n+7)^{\circ}}

{:\implies \quad \sf 6n-5n=7+4}

{:\implies \quad \bf \therefore \quad \underline{\underline{n=11}}}

<em>This is the required answer </em>

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Answer:

6,483.75

Step-by-step explanation:

Calculation to find the interest paid by B after 3/2 year

First step is to calculate the Compound interest amountUsing this formula

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T represent Time=3/2 years

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Compound interest amount= 32,500(1 + 6.25/100)^2*3/2

Compound interest amount= 32,500([1+.0625)^3

Compound interest amount= 32,500(1.0625)^3

Compound interest amount= 32,500 *1.1995

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Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Ro
saw5 [17]

Answer:

(a) P(0 <= Z <= 2.24)  = 0.4927

(b) P(0 <= Z <= 2)  = 0.4773

(c) P(-2.60 <= Z <= 0) = 0.4953

(d) P(-2.60 <= Z <= 2.60) = 0.9906

(e) P(Z <= 1.64)  = 0.9495

(f) P(-1.75 <= Z) = 0.0047

(g) P(-1.60 <= Z <= 2.00) =  0.9425

(i) P(1.60 <= Z)=0.0548

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Step-by-step explanation:

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using the STANDARD NORMAL DISTRIBUTION TABLE

P(0 <= Z <= 2.24) = 0.9927 -  0.5  = 0.4927

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= 0.9773 -  0.5  = 0.4773

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=   0.5 - 0.0047 = 0.4953

(d) P(-2.60 <= Z <= 2.60) = P(Z <= 2.6)- P(-2.60)

=   0.9953 - 0.0047 = 0.9906

(e) P(Z <= 1.64)  = 0.9495

(f) P(-1.75 <= Z) =1 - P(Z < 2.6) = 1 -  0.9953  = 0.0047

(g) P(-1.60 <= Z <= 2.00) = P(Z <= 2.0)- P(-1.60)

= 0.9773- 0.0548  = 0.9425

(i) P(1.60 <= Z)=1 - P(Z < 1.6) = 1 -  0.9452  = 0.0548

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=0.9938 - 0.0062 = 0.9876

7 0
3 years ago
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