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Fed [463]
3 years ago
14

Pls pls helpppppppppppppp

Mathematics
2 answers:
vovikov84 [41]3 years ago
8 0

Answer:

isnt it already answerd

Step-by-step explanation:

...

weqwewe [10]3 years ago
6 0
512 is the answer to the second one
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Daniels print shop purchased a new printer for $35,000. Each year it depreciates at rate of 5%. How much will the printer be wor
Savatey [412]
Ab^x
a: initial value
b: value remaining after depreciation per year (in percentage)
x: number of years that have passed

35000(0.95)^8= 23219.7151

Round to the nearest hundredth value:
About $23219.72

Let me know if you have any questions :)
7 0
4 years ago
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
4 years ago
I need Help plsssss!!!!!
laiz [17]

Answer:

2x - 3

x - 9

Step-by-step explanation:

The root of a problem is the x value that makes the equation equal to zero.

If the factored form of the equation is (2x-3)(x-9) that means if either 2x - 3 or x - 9 is equal to zero, the entire equation will equal zero, because zero times any number is equal to zero.  

Therefore you must solve for (2x-3)=0 and (x-9)=0

4 0
3 years ago
PLEASE HELP FAST!!!
larisa [96]
I believe the answer is 4
6 0
3 years ago
Read 2 more answers
A parabolic microphone used on the sidelines of a professional football game uses a reflective dish 24 in. wide and 5 in. deep.
madreJ [45]

Answers:

(1 Question in written form): 7.2 inches.

(2 Question in the picture): Option (D) (y+1)^2=2(x+3) and  F=(\frac{-5}{2},-1) and x=\frac{-7}{2}

Explanations:

1. (Question in written form):

First you need to know the standard form of a parabola (considering it opens in +x direction and the vertex of the parabola is at origin), which is as follows:

(y-k)^2 = 4p(x-h)

Since the vertex of the parabola is at origin, h = 0 and k = 0. The above equation will now become:

y^2 = 4px ---- (A)


Where p is the distance between the vertex and the focus of a parabola, which we need to find (or where the microphone should be placed).

As the vertex is assumed to be placed at the origin, the parabolic dish, which is 24 inches wide, will be split evenly on both sides of the y axis (as the opening of the parabola is in x-axis—stated above), giving the distance of 12 inches from each sides of y axis (12 inches + 12 inches = 24 inches). Since it (parabolic microphone) is 5 inches deep, the coordinates will become: (5, +12) and (5, -12).

Plug any of the points—(5,+12) or (5,-12)—in equation (A), you will get the following:

(12)^2 = 4p(5) \\ 144 = 4p(5) \\ \frac{144}{5} = 4p \\ \frac{144}{5*4} = p \\ p=7.2\thinspace inches

Hence, the correct answer is 7.2 inches.


2. (Question in the picture):

First we need to write the following equation in the standard form:

y^2 - 2x + 2y -5 = 0 ----- (B)


The standard form of parabola is:

(y-k)^2 = 4p(x-h) ----- (C)


Rearrange equation (B) and solve as follows:

y^2-2x+2y-5=0 \\ y^2 + 2y - 5 = 2x \\ y^2 + 2y +1 = 2x + 6 \\ y^2 + y + y + 1 = 2(x+3) \\ y(y+1)+1(y+1)=2(x+3)\\(y+1)^2=2(x+3)

You can write the above equation as follows:

(y-(-1))^2 = 4(\frac{1}{2})(x-(-3)) ----- (D)

Now compare equation (D) with (C), we will get:

Focus = (h+p, k) = (-3+(1/2), -1)

Focus: (\frac{-5}{2},-1)


Now, to find x, use the following formula:

x = h - p

x = -3-\frac{1}{2} = \frac{-7}{2}


Hence, the correct option is (D) -> F=(\frac{-5}{2},-1) and x=\frac{-7}{2}

4 0
3 years ago
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