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3 years ago

14

Which would most likely be true in osteoporosis? osteoclast activity is high. osteoclast and osteoblast activity are normal. ost

eoblast activity is high?

1 answer:

Setler [38]3 years ago

5 0

Its 8 please help me

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According to Plato and the traditional definition of knowledge, having a true belief is sufficient to have knowledge.A. TrueB. F

vovangra [49]

Answer:

False

Explanation:

This statement is false because knowledge is more like a way of getting at the truth.

A justified and true belief is necessary and sufficient for knowledge. In philosophy, the study of knowledge is called epistemology, and according to Plato and traditional definition, knowledge is "justified true belief."

6 0

2 years ago

Which part of a molecule determines the type of amino acid?

Slav-nsk [51]

The tRNA molecule determines the type of amino acid!

4 0

2 years ago

Read 2 more answers

assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar

svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

$E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}$

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

$100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\ 53.57 = \dfrac{4}{[K^+]_{in}}$

$[K^+]_{in} = \dfrac{4}{53.57}$

$[K^+]_{in} = 0.0476$

For [Cl⁻]:

$100 \times 10^{-3} = -0.0257 \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$-3.981 = \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$0.01867 = \dfrac{120}{[Cl^-]_{in}}$

$[Cl^-]_{in} = \dfrac{120}{0.01867}$

$[Cl^-]_{in} =6427.4$

For [Na⁺]:

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$53.57= \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$[Na^+]_{in}= 2.70$

6 0

2 years ago

2. provides energy to a cell

pishuonlain [190]

Answer: Mitochondria

Explanation: The mitochondria make energy within the cell

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3 years ago

What is stimulated by high extracellular fluid volume (ECFV) and works to increase GFR and urine output?

r-ruslan [8.4K]

Stretching of the atrial muscle cells releases a hormone called atrial natriuretic factor (ANF). ANF relaxes the juxtaglomerular (JG) cells of the afferent arteriole and thereby increases GFR and urine output.

3 0

3 years ago