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Goshia [24]
2 years ago
7

Hellpppp me please this test is my whole life and if I don’t pass I’m ruined for life so please HELPPPP MEEEEE

Mathematics
1 answer:
Elanso [62]2 years ago
3 0

Answer:

expanded form: 5 * 5 * 5

value: 125

Step-by-step explanation:

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Which rule yields the dilation of the figure QRST centered at the origin?
denis-greek [22]

A) (x, y) → (3x, 3y)

<h2>Explanation:</h2>

When you dilate an object, you enlarge or reduce the size of it. To do this, we need a scale factor which allows us to make the object larger or smaller depending on the value of that factor. Let's call this factor as k, then it is true that:

  • If k > 1, the object will be larger than the original one.
  • If k < 1, the object will be smaller than the original one.

If the dilation is performed centered at the origin, then corresponding points of the original and dilated figures will be connected by straight lines, being the center of dilation the point where all the lines meet.

The only option that meets this requirement is:

A) (x, y) → (3x, 3y)

Whose scale factor is k = 3 making the dilated figure larger than the original one.

<h2>Learn more:</h2>

Dilation: brainly.com/question/10946046

#LearnWithBrainly

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2 years ago
A ball is thrown from a height of 70 meters with an initial downward velocity of 10/ms. The ball's height h (in meters) after t
dmitriy555 [2]

Answer:h=−5t2−10t+70

Step-by-step explanation:

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3 years ago
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C

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One of the legs of a right triangle measures 2 cm and its hypotenuse measures 18 cm.
denpristay [2]

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17.9

Step-by-step explanation:

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2 years ago
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad &#10;C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}&#10;\\\\\\&#10;AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad &#10;D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}&#10;\\\\\\&#10;BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}&#10;\\\\\\&#10;BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]&#10;\\\\\\&#10;4[15]\implies 60

7 0
2 years ago
Read 2 more answers
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