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fiasKO [112]
2 years ago
7

I really need some help with this whoever helps I will give you the brainliest answer

Mathematics
1 answer:
yarga [219]2 years ago
6 0

Answer:

standard form: y = -x^2 + 15x

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What is the argument of -5\sqrt{3}+ 5i?
Shtirlitz [24]

Answer:

150 degrees

Step-by-step explanation:

Graphing the complex number we see the angle terminates in the second quadrant. This means the argument, the angle, will be between 90 degrees and 180 degrees.

So if we create a right triangle with that point after graphing it. We see the height of that triangle is 5 because that is the imaginary part. The base of that triangle has length 5\sqrt{3}. The problem is this doesn't give us any part of the angle we want, but it does give us the complementary of the part of the angle that is in second quadrant.

Let's find the complementary angle.

So the opposite side of the complementary angle is 5.

The adjacent side of the complementary angle is 5\sqrt{3}.

\tan(\theta)=\frac{5}{5\sqrt{3}}

\tan(\theta)=\frac{1}{\sqrt{3}}

\theta=\tan^{-1}(\frac{1}{\sqrt{3}})

\theta=30

So 90-30=60.

The answer therefore 60+90=150.

4 0
2 years ago
Plz help. due tomorrow!
Aleonysh [2.5K]
What idk jk sorry trying to be funny like always but what is the question I have no picture
3 0
3 years ago
In a group of 60 numbers, average of
Arada [10]

Answer:

c. 18

Step-by-step explanation:

First, you would find the total sum of the 60 numbers. The average is always the sum of the numbers divided by the number of numbers.

35*18=630

15*10=150

Now we do not know how many numbers the last group has. However, we can find it out doing 60-35-15 to see how many numbers are left. There would be 10 numbers left

10*30=300

630+150+300=1080

1080/60=18

Hence, the answer is C(18)

4 0
3 years ago
What is the interquartile range for this data?<br><br> 120, 140, 160, 180, 200, 220, 240
Nutka1998 [239]

Step-by-step explanation:

The data is already in ascending order.

The lower half of the data (120, 140, 160)

has the median 140.

180 is the median of the entire data.

The upper half of the data (200, 220, 240)

has the median 220.

Interquartile Range = 220 - 140 = 80.

6 0
3 years ago
Consider the matrices.
algol13

Answer:

Attached

Step-by-step explanation:

5 0
3 years ago
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