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uranmaximum [27]
3 years ago
13

Write an equation for a function that has vertical asymptotes at x=3 & x=-10

Mathematics
1 answer:
stepan [7]3 years ago
7 0

Answer:

\frac{5}{ {x}^{2}   + 7x - 30}

Step-by-step explanation:

We can write a rational function.

We need to make sure our denominator both have zeroes at 3 and 10.

Set an equation equal to zero to find the function

0 - x = 3

0 - x =  - 10

0 - ( - 3) =  = 3

0 - 10 = 10

So we would represent that's as

x - 3

and

x + 10

Multiply the two binomial together.

(x - 3)(x + 10) =  {x}^{2}  + 7x  - 30

Let our numbetator be any interger.

Use any equation as long as the quadratic is the denominator and the interger is the numerator.

\frac{5}{ {x}^{2} + 7x - 30 }

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If the numbers below were ordered from least to greatest, which number could you use to replace the blank? 0.20,2/5 □ , 3/4,8/10
faust18 [17]
1/2 would work for the blank space

because as shown in the image you could relate it to a whole for each one and put it to 100 to figure out what the blank could be

the 0.20 can be converted to 1/5 so that way you can put everything into the 100 group

8 0
4 years ago
What is value of 5 in 2 500.7
umka21 [38]

Answer:

500

Step-by-step explanation:

Since the 5 is in the hundreds place in the number 2500.7, its value is 5 * 100 = 500.

6 0
2 years ago
Read 2 more answers
Solve<br>0.9(7x + 14) = 1.5 - (x + 2)
Triss [41]

\\ \sf\longmapsto 0.9(7x+14)=1.5-(x+2)

\\ \sf\longmapsto 6.3x+12.6=1.5-x-2

\\ \sf\longmapsto 63x+12.6=-x-0.5

\\ \sf\longmapsto 63x+x=-0.5-12.6

\\ \sf\longmapsto 64x=-13.1

\\ \sf\longmapsto x=\dfrac{-13.1}{64}

\\ \sf\longmapsto x=0.2

7 0
3 years ago
The set of the consecutive odd numbers 1, 3, 5, 7, ... , N has a sum of 400. How many numbers are in the set?
Amanda [17]

Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.

First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.

Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:

         1, 3, 5, 7, 9, 11, 13, 15 .

Number of items in the set . . . 8
Sum of all the items in the set . . . 64

Hmmm.  That's interesting.  64 happens to be the square of 8 . 
Do you think that might be all there is to it ?

Let's check it out:

Even-numbered lists of odd numbers:

1, 3                                   Items = 2, Sum = 4
1, 3, 5, 7                           Items = 4, Sum = 16
1, 3, 5, 7, 9, 11                 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .

Amazing !  The sum is always the square of the number of items in the set !

For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.

I slogged through it on my calculator, and it's true.

I never knew this before.  It seems to be something valuable
to keep in my tool-box (and cherish always).


3 0
3 years ago
a horse weight decreases by 1/2 pound per week at this rate how many weeks will it take for the horse to visit total of 5 1/2 wr
kykrilka [37]

Answer:

11 weeks

Step-by-step explanation:

5÷1/2=10

10+1=11

Sorry if I'm wrong

4 0
3 years ago
Read 2 more answers
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