ILL MARK AS BRAINLIST IF U GET IT RIGHT it’s khan

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

8 0

Answer:

Step-by-step explanation:

given that x and y are proportional, they can be expressed as y = rx, where r is the proportionality constant. Thus, we can solve for r by doing y/x in any given point.

$\frac{8}{1.6} = \frac{15}{3} = \frac{22}{4.4} = 5$

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(a+b+c)(d+e+f)(a+b+c)(d+e+f)(a+ b+ c) <br> ( d+e+ f)

8090 [49]

Hi the expanded form is

$d^3 a^3 + e^3 a^3 + f^3 a^3 + 3 d e^2 a^3 + 3 d f^2 a^3 + 3 e f^2 a^3 + 3 d^2 e a^3 + 3 d^2 f a^3 + 3 e^2 f a^3 + 6 d e f a^3 \\+ 3 b d^3 a^2 + 3 c d^3 a^2 \\+ 3 b e^3 a^2 + 3 c e^3 a^2 + 3 b f^3 a^2 \\+ 3 c f^3 a^2 + 9 b d e^2 a^2 + 9 c d e^2 a^2 + 9 b d f^2 a^2 + 9 c d f^2 a^2\\ + 9 b e f^2 a^2 + 9 c e f^2 a^2 + 9 b d^2 e a^2 + 9 c d^2 e a^2 + 9 b d^2 f a^2 + 9 c d^2 f a^2 \\+ 9 b e^2 f a^2 + 9 c e^2 f a^2 + 18 b d e f a^2$

$+ 18 c d e f a^2 + 3 b^2 d^3 a + 3 c^2 d^3 a \\+ 6 b c d^3 a + 3 b^2 e^3 a + 3 c^2 e^3 a + 6 b c e^3 a + 3 b^2 f^3 a \\+ 3 c^2 f^3 a + 6 b c f^3 a + 9 b^2 d e^2 a \\+ 9 c^2 d e^2 a + 18 b c d e^2 a + 9 b^2 d f^2 a\\ + 9 c^2 d f^2 a + 18 b c d f^2 a + 9 b^2 e f^2 a + 9 c^2 e f^2 a + 18 b c e f^2 a + 9 b^2 d^2 e a \\+ 9 c^2 d^2 e a + 18 b c d^2 e a + 9 b^2 d^2 f a + 9 c^2 d^2 f a + 18 b c d^2 f a \\+ 9 b^2 e^2 f a + 9 c^2 e^2 f a + 18 b c e^2 f a$

$+ 18 b^2 d e f a + 18 c^2 d e f a + 36 b c d e f a \\+ b^3 d^3 + c^3 d^3 + 3 b c^2 d^3 + 3 b^2 c d^3 + b^3 e^3 + c^3 e^3 \\+ 3 b c^2 e^3 + 3 b^2 c e^3 + b^3 f^3 + c^3 f^3 + 3 b c^2 f^3 + 3 b^2 c f^3 + 3 b^3 d e^2 \\+ 3 c^3 d e^2 + 9 b c^2 d e^2 + 9 b^2 c d e^2 + 3 b^3 d f^2 + 3 c^3 d f^2 + 9 b c^2 d f^2 \\+ 9 b^2 c d f^2 + 3 b^3 e f^2 + 3 c^3 e f^2$

$+ 9 b c^2 e f^2 + 9 b^2 c e f^2 + 3 b^3 d^2 e \\+ 3 c^3 d^2 e + 9 b c^2 d^2 e + 9 b^2 c d^2 e + 3 b^3 d^2 f + 3 c^3 d^2 f \\+ 9 b c^2 d^2 f + 9 b^2 c d^2 f + 3 b^3 e^2 f + 3 c^3 e^2 f + 9 b c^2 e^2 f \\+ 9 b^2 c e^2 f + 6 b^3 d e f + 6 c^3 d e f + 18 b c^2 d e f + 18 b^2 c d e f$